Answer:
3. 0.5 sec.
Explanation:
A bullet fired horizontally follows a projectile motion, which consists of two independent motions:
- A horizontal motion with constant speed
- A vertical motion with constant acceleration, g = 9.8 m/s^2, towards the ground
The time taken for the bullet to reach the ground can be calculated just by considering the vertical motion:
![y(t) = h + v_{0y} t - \frac{1}{2}gt^2](https://tex.z-dn.net/?f=y%28t%29%20%3D%20h%20%2B%20v_%7B0y%7D%20t%20-%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
where y is the vertical position at time t, h is the initial height, and
is the initial vertical velocity of the bullet.
Since the bullet is fired horizontally,
. So the equation becomes
![y(t) = h - \frac{1}{2}gt^2](https://tex.z-dn.net/?f=y%28t%29%20%3D%20h%20-%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
And the time that the bullet takes to reach the ground can be found by requiring y=0 and solving for t:
![t=\sqrt{\frac{2h}{g}}](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B%5Cfrac%7B2h%7D%7Bg%7D%7D)
As we can see, in this equation there is no dependance on the initial speed of the bullet: therefore, if the bullet is fired still horizontally but with a different speed, it will still take the same time (0.5 s) to reach the ground.