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dangina [55]
2 years ago
12

My new unit of math isn’t covered on Brainly

Mathematics
1 answer:
bezimeni [28]2 years ago
4 0

Answer:

Hello

Step-by-step explanation:

have you tried socratic? socratic is just like brainly and it gives you the right answers most of the time.

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Which inequality is true when the value of R is 18? I'ma shower the answers i can choose in the picture ​
musickatia [10]

Answer:

See below:

Step-by-step explanation:

Hello! We can check to see if the inequality is true by replacing r with 18 as we have been told to find them in which 18 as r makes the equation true.

So our equations to test for are:

-r-3>-6\\-r+3

We can input 18 as r and then we see the following are correct:

1. No, as a -21 is not greater than -6

2. Yes, as -15 is less than 6.

3. No, as 21 is not greater than 6

4. No, as -15 is not greater than 6.

Cheers!

7 0
3 years ago
What would B and C equal?
finlep [7]

Answer:

b=42

c=180

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A hunter is practicing his aim using a practice target. He takes 5 shots. All 5 shots hit the target, but they do not hit or sur
IRINA_888 [86]

Answer:

D

Step-by-step explanation:

Accuracy refers to how close measurements are to the "true" value (which is the target in this case), while precision refers to how close measurements are to each other.

Since the arrows fall away from the bullseye and are spread out I would classify this as low accuracy and low precision.

3 0
3 years ago
75 = 30q ( 30q means multiply )
dalvyx [7]

Answer:

75 = 30q

q = 75/30

q = 2.5

Hope it helps

3 0
3 years ago
Consider f and c below. f(x, y, z) = yzexzi + exzj + xyexzk,
Jet001 [13]

Answer:

f(x,y,z)=ye^{xz}+C  

Step-by-step explanation:

We can write the given expression as :

\vec f(x,y,z)=yze^{xz}\,\vec\imath+e^{xz}\,\vec\jmath+xye^{xz}\,\vec k

As given,   f = ∇f.

∇f = \dfrac{\partial f}{\partial x}i  + \dfrac{\partial f}{\partial y}j  +\dfrac{\partial f}{\partial z}k 

We can write the partial derivative with respect to x, y and z.

\dfrac{\partial f}{\partial x}=yze^{xz}       ___(Equation 1)

\dfrac{\partial f}{\partial y}=e^{xz}               ______(Equation 2)

\dfrac{\partial f}{\partial z}=xye^{xz}             ______(Equation 3)

Take equation 2 and integrate with respect to y,

\dfrac{\partial f}{\partial y}=e^{xz}

f(x,y,z)=ye^{xz}+a(x,z)           ----------Equation 4

Derivate both sides w.r.t x , we get :

\frac{d}{dx}(yze^{xz})=yze^{xz}+\dfrac{\partial a}{\partial x}

or

\dfrac{\partial a}{\partial x}=0

integrate

a(x,z)=b(z)

put in equation 4 ,

we get :

f(x,y,z)=ye^{xz}+b(z)

take derivative wrt z

\frac{d}{dz} (ye^{xz}+b(z))\impliesxye^{xz}=xye^{xz}+\frac{db}{dz}

we can take here:

\frac{db}{dz} = 0

integrate:

\int\ {\frac{db}{dz} } \, =\int0

b(z) = C

The function can be written as :

from equation 4 :

f(x,y,z)=ye^{xz}+C  

Where C is a constant.

4 0
2 years ago
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