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3 years ago

Given two balanced equations, each representing a reaction:

Chemistry

1 answer:

Nitella [24]3 years ago

4 0

Answer:

There is a hack in forms that forms gives u the answer hold ctrl + u, and scrool to the bottom he read the part with the question and there will be an answer.

Mark as brainliest if im right good luck

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What is extrapolation?

bixtya [17]

Answer:

A. Predicting data that fall beyond a known data point

Explanation:

Extrapolating is unreliable because you are predicting data outside of the data range - anything could happen for the data to stop following the trend or pattern

8 0

3 years ago

In the laboratory a general chemistry student finds that when 2.84 g of KClO4(s) are dissolved in 107.70 g of water, the tempera

vredina [299]

Answer : The enthalpy change of dissolution of $KClO_4$ is 54.3 kJ/mole

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $1.55J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = 107.70 g

$\Delta T$ = change in temperature = $T_2-T_1=(22.80-20.34)=2.46^oC$

Now put all the given values in the above formula, we get:

$q=[(1.55J/^oC\times 2.46^oC)+(107.70g\times 4.184J/g^oC\times 2.46^oC)]$

$q=1112.3J=1.1123kJ$

Now we have to calculate the enthalpy change of dissolution of $KClO_4$

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 1.1123 kJ

m = mass of $KClO_4$ = 2.84 g

Molar mass of $KClO_4$ = 138.55 g/mol

$\text{Moles of }KClO_4=\frac{\text{Mass of }KClO_4}{\text{Molar mass of }KClO_4}=\frac{2.84g}{138.55g/mole}=0.0205mole$

$\Delta H=\frac{1.1123kJ}{0.0205mole}=54.3kJ/mole$

Therefore, the enthalpy change of dissolution of $KClO_4$ is 54.3 kJ/mole

5 0

4 years ago

How to purify ammonia

padilas [110]

In order to purify ammonia to high purity, two basic methods are used. The older one consists in passing gaseous ammonia containing 80 ppm of impurities under atmospheric pressure through liquid ammonia with dissolved metallic sodium.

5 0

3 years ago

The Gateway Arch in St. Louis, MO is approximately 630 ft tall. How many U.S. half dollars would be in a stack of the same heigh

zhannawk [14.2K]

Answer:

To equal the height of the Gateway Arch in St. Louis, it would take <u>76810 half dollars. </u>

Explanation:

If the Gateway Arch in St. Louis is 630 feet high, how many half dollars will it take to equal the height if each half dollar is 2.15mm thick?

First, we convert the ft to cm and the cm to mm.

- 1 ft = 30.48 cm

630 ft = 19202.4 cm

- 19202.4 cm = 192024 mm

Now, if a half dollar is 2.15 mm thick, how many half dollars would it take to equal the height of 192024 mm?

1 half dollar = 2.15 mm

X = 192024 mm

X = 192024 mm / 2.15 mm

X = 76810 half dollars.

5 0

3 years ago

In the chemical equation 3c2h4 how many atoms of carbon are represented

Scorpion4ik [409]

An example.
water is H2O

2 hydrogen, 1 oxygen

so the number to the right means how much of what is on the left.

so it looks like 2, because C2, but look at the 3 at the beginning. that means
3 (c2h4)

so 6 carbons, 12 hydrogen

the ratio of c2 to h4 doesn't change it's always 1:2.

but the 3 at the front is a different number relating to how much you have

5 0

3 years ago