The scatterplot shows how many miles Marissa jogged over 10 days. Which statements are true? Check all that apply.
Marissa jogged 5 miles on the first day.
Marissa jogged 6 miles on the second day.
Marissa jogged 9 miles on the third day.
Marissa jogged 3 miles on the fourth day.
Marissa jogged 3 miles on the ninth day.vvvvvThe scatterplot shows how many miles Marissa jogged over 10 days. Which statements are true? Check all that apply.
Marissa jogged 5 miles on the first day.
Marissa jogged 6 miles on the second day.
Marissa jogged 9 miles on the third day.
Marissa jogged 3 miles on the fourth day.
Marissa jogged 3 miles on the ninth day.Answer:
Step-by-step explanation:
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Answer:
83,749 bottles
Step-by-step explanation:
Each bottle contain = 355ml
Total water need to pack = 29,730,895 ml
So, we can calculate the number of bottles by using following formula,
Number of bottles required = Total water ÷ Each bottle contain
by putting the value, we get
Number of bottles required = 29,730,895 ÷ 355
= 83,749
Hence, total number of bottles required is 83,749.
Answer:
-7+c
Step-by-step explanation:
distribute the - 1
I think the answer to your question is 15 hope this helps
Hi there!
Many things we do in everyday life have a variety of ways we can go about accomplishing them, but we most often choose the most practical and efficient method.
Efficiency saves time and prevents over-complication, which may lead to errors.
We might need to identify the specifics of the task and its circumstances to be able to determine the most efficient method to do it.
Solving a quadratic equation, we also must think about the most efficient method that can lead us to the correct answer. And doing so, we must identify the circumstances of the equation; Can it be solved by factoring? Is it easy to factor? What form is this quadratic equation in?
For example, let's say we're given the equation (x-1)(x+2)=0. This is an equation in factored form. In these kinds of scenarios, we can <em>easily</em> solve by setting each term equal to 0 (the Zero Product Property). This is the <em>most efficient </em>method:
x-1=0 --> x=1
x+2=0 --> x=-2
I hope this helps!