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zmey [24]
3 years ago
14

Which of the following best describes the velocity of an object? *

Physics
2 answers:
mixas84 [53]3 years ago
7 0

A. 30 m/s . . . speed

B. 30 m to the East  . . . displacement

C. 30 m/s to the East  . . . <em>velocity</em>

D. 30 m . . . distance

Elena-2011 [213]3 years ago
3 0
D fam hope this helps
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A certain lightbulb has a tungsten filament with a resistance of 26 Ω when cold and 170 Ω when hot. If the equation R = R0 [1 +
iris [78.8K]

Answer:

Explanation: The equation that relates resistance of tungsten at different temperatures is as follows

R = R₀ [1 + α ∆T]  , R₀ is resistance at lower temperature , R is resistance at higher temperature . α is temperature coefficient of resistivity and ∆T is rise in temperature .

Putting the values

170 = 26 [1 + .0045 ∆T]

∆T = 1230.75

lower temperature = 40◦C

higher temperature = 1230 + 40

= 1270◦C

5 0
3 years ago
A ferry approaches shore moving north waith a speed of 6.1 m/s relative to the dock. A person on the feery walks from one side o
stepladder [879]

Answer:

6.18 m/s

Explanation:

Given that a ferry approaches shore, moving north with a speed of 6.1 m/s relative to the dock. A person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.0 m/s relative to the ferry Part. What is the speed of the person relative to the dock?

The speed of the person can be calculated by using pythagorean theorem.

Let the speed of the person = S

S^2 = 6.1^2 + 1^2

S^2 = 38.21

S = sqrt ( 38.21)

S = 6.18 m/s

Therefore, the speed of the person relative to the dock is 6.18 m/s

5 0
3 years ago
Include units with all of your answers. A 1.84 kg bucket full of water is attached to a 0.76 m long string.
aleksandrvk [35]
<span>c. What is the magnitude of the tension in the string at the bottom of the circle if you are swinging it at 3.37 m/s? </span>
7 0
3 years ago
A wall clock has a minute hand with a length of 0.53 m and an hour hand with a length of 0.26 m. Take the center of the clock as
ollegr [7]

Answer:

a  =1.61 × 10⁻⁶ m/s²

Explanation:

given,

length of minute hand = 0.53 m

length of hour hand = 0.26 m

the time taken by the minute hand to complete one revolution is T=3600 s

the angular frequency is

                        \omega =\dfrac{2\pi }{T}

                         \omega =\dfrac{2\pi }{3600}

                         \omega=0.001745 rad/sec

the acceleration is  

                                a = r \omega^2

                                a = (0.53) \times (0.001745)^2

                                       a  =1.61 × 10⁻⁶ m/s²

3 0
4 years ago
An electron has a velocity of 3.2 x 10^6 m/s. What is its’ momentum? (b) What is its’ wavelength? (c) What other objects/materia
Romashka [77]

Answer:

P = 2.91*10^{-24} kg m/s

\lambda = 2.73 *10^{-10} m

size of atom hat lie in range of 1 to 5 Angstrom

\Delta x = 0.2272 Angstrom

Explanation:

A) MOMENTUM

p = mv

where m is mass of electron

so momentum p can be calculated as

p = 9.11*10^{-31} *3.2*10^{6}

P = 2.91*10^{-24} kg m/s

b) wavelength

\lambda = \frac{h}{mv}

where h is plank constant

so\lambda = \frac{6.626*10^{-34}}{2.91*10^{-24}}

\lambda = 2.73 *10^{-10} m

c) size of atom hat lie in range of 1 to 5 Angstrom

d) from the information given in the question we have

\frac{\Delta v}{v} = 0.1

\Delta v = 0.1 v

we know that

\Delta p *\Delta x = \frac{h}{4\pi}

m \Delta v \Delta x =\frac{h}{4\pi}

\Delta x = \frac{h}{m \Delta v}

\Delta x  = \frac{2.272}{0.1}                      [\Delta v = 0.1 v]

\Delta x = 0.2272 Angstrom

7 0
4 years ago
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