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frozen [14]
3 years ago
9

Please help I’ll mark you as brainiest

Mathematics
1 answer:
mojhsa [17]3 years ago
3 0

Answer:

V = 10 x 9 x (1/3)

V = 30 in³

Step-by-step explanation:

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Help me please guys if you don’t mind
zubka84 [21]

Answer:

Greatest common factor = [2x - 5][x + 2]

Step-by-step explanation:

Given equation:

2x² - x - 10

Find:

Greatest common factor

Computation;

⇔ 2x² - x - 10

By splitting mid term

⇔ 2x² - [5 - 4]x - 10

Multiply by 'x'

⇔ 2x² - 5x + 4x - 10

taking x and 2  as common

⇔ x[2x - 5] + 2[2x - 5]

taking [2x - 5]  as common

⇔ [2x - 5][x + 2]

Greatest common factor = [2x - 5][x + 2]

6 0
3 years ago
What is 280 as a fraction? Show your work.
Katen [24]
Any number divided by 1 is still that number (it stays the same).
So you can rewrite 280 as 280/1, which is a fraction.

With 280/1, you can also get an equivalent fraction by multiplying the numerator and denominator by a number, let's say 2.
So multiplying the numerator 280 by 2 would get 560, the denominator would be 2. So another equivalent fraction would be 560/2
5 0
3 years ago
Read 2 more answers
If someone could please help me on this it would be amazing thank you so much
ohaa [14]

Answer:

7 cm squared

Step-by-step explanation:

not sure if its right but thats what i got round up to

8 0
3 years ago
a shipping box will be filled with two different machine parts. one type of machine part weights 0.15 ponds and the other weight
gulaghasi [49]
\frac{x}{2} =0.15 hope so this helps

8 0
3 years ago
What are the period and phase shift for f(x) = 3 tan(4x + π)?
Y_Kistochka [10]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


now.. with that template above in mind, let's see yours


\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

7 0
3 years ago
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