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kondaur [170]
4 years ago
13

How many moles are in 100. mg of c26h23n7o2

Chemistry
1 answer:
8_murik_8 [283]4 years ago
4 0

Answer:

4.1143797572516005

Explanation:

I think this is what you're asking, I'm not sure

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Solubility of a compound in water can be referred to as the amount of the compound that can be dissolved in 1 L of the solvent (water) at any given temperature. Solubility of a compound can be expressed in the units of g/L or mg/L.

Given that the solubility of calcium carbonate in water = 14 mg/L

We have to calculate the volume of water that can dissolve 11 g of calcium carbonate.

Converting 11 g calcium carbonate to mg:

11g *\frac{1000mg}{1g} =11,000 mg

Volume of water that would dissolve 11000 mg calcium carbonate

                             = 11000 mg CaCO_{3}*\frac{1L}{14 mg}

                             =785.7 L

Rounding the volume 785.7 L to two significant figures, we get 790 L water.

Therefore, we would need 790 L water to completely dissolve 11 g of calcium carbonate.

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BlackZzzverrR [31]
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