Question

Calculate the equilibrium constant for the reaction using the balanced chemical equation and the concentrations of the substances at equilibrium.
Use the

appropriate significant figures in reporting the answers.

CO(g) + H2O(g) ⇌ CO2(g) + H2(g) [CO] = 0.0590 M; [H2O] = 0.00600 M;

[CO2] = 0.0410 M; [H2] = 0.0410 M

K =______________-

Answer 1

Answer:

4.75 is the equilibrium constant for the reaction.

Explanation:

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

Equilibrium concentration of reactants :

$[CO]=0.0590 M,[H_2O]=0.00600 M$

Equilibrium concentration of products:

$[CO_2]=0.0410 M,[H_2]=0.0410 M$

The expression of an equilibrium constant is given by :

$K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}$

$K_c=\frac{0.0410 M\times 0.0410 M}{0.0590M\times 0.00600 M}$

$K_c=4.75$

4.75 is the equilibrium constant for the reaction.