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cricket20 [7]
2 years ago
8

Limitations of Lewis dot structure

Chemistry
1 answer:
WARRIOR [948]2 years ago
5 0

Answer:

Limitations of Lewis structures: resonance structures and violations of the octet rule (odd electron, hypovalent and hypervalent molecules). (1) Shapes of simple molecules with “central” atoms. (2) Configuration: the position of atoms in space about a central atom. The VSEPR theory of configuration.

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HELP PLEASE 100 points!!!
djyliett [7]

Answer:

by the looks of it the answer you have is correct

Explanation:

3 0
2 years ago
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the equilibrium concentration of hydroxide ion in a saturated iron(ii) hydroxide solution is 1.2 x 10^-5 M at a certain temperat
Anit [1.1K]

From the calculation as shpwn in the procedure below, the equilibrium constant of the substance is 6.9 * 10^-15.

<h3>What is equilibrium constant?</h3>

The equilibrium constant for the solubility of aa solid in solution is called the solubility product Ksp. The Ksp shows the extent to which a solid is dissolved in solution.

Given that;

Fe(OH)2 ⇄Fe^2+ + 2(OH)^-

Ksp = s(2s)^2

We have s as 1.2 x 10^-5 M

So

Ksp = 4s^3

Ksp = 4( 1.2 x 10^-5 )^3

Ksp = 6.9 * 10^-15

Learn more about Ksp:brainly.com/question/27132799

#SPJ1

8 0
2 years ago
I need helpppp
Nata [24]

Answer:

Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃

The coefficients are: 1, 6, 3, 2

Explanation:

__Fe₂(SO₄)₃ + __KOH —> __K₂SO₄ + __Fe(OH)₃

To determine the correct coefficients, we shall balance the equation. This can be obtained as follow:

Fe₂(SO₄)₃ + KOH —> K₂SO₄ + Fe(OH)₃

There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 2 before Fe(OH)₃ as shown below:

Fe₂(SO₄)₃ + KOH —> K₂SO₄ + 2Fe(OH)₃

There are 6 atoms of OH on the right side and 1 atom on the left side. It can be balance by writing 6 before KOH as shown below:

Fe₂(SO₄)₃ + 6KOH —> K₂SO₄ + 2Fe(OH)₃

There are 6 atoms of K on the left side and 2 atoms on the right side. It can be balance by writing 3 before K₂SO₄ as shown below:

Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃

Now, the equation is balanced.

Therefore, the coefficients are: 1, 6, 3, 2

3 0
2 years ago
What mass of oxygen reacts when 84.9 g of iron is consumed in the following reaction: Fe+O2= Fe2O3
konstantin123 [22]
First we will calculate the number of moles of Iron:
n =  \frac{m}{M}&#10;, where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.
n= \frac{84.9}{55.845} = 1,52 moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So 1,52= \frac{mOxygen}{32} where 32 is the Atomical Weight of Oxygen (16 x 2).
=>mOxygen=32*1,52=48,64g
6 0
3 years ago
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Which tool was most likely used in a procedure if the lab report shows that approximately 300 mL of water was used ?
Travka [436]

Graduated Cylinder is the answer to this.


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3 years ago
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