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2 years ago

If the solubility of a gas in water at 25°C is 22.25 mg/L at 2.5 atm of pressure, what is its solubility (in mg/L) at 25°C

Chemistry

1 answer:

tamaranim1 [39]2 years ago

8 0

Answer:

8.9 mg/l

Explanation: Temp doesnt matter so throw that out automatically then your equation is;

S1/P1=S2/P2

We are looking for S2 and that equation is;

S2=S1*P2/P1 and that is S2=22.25*1/2.5

A little bit of simple math and you get your answer: 8.9 mg/l

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Answer: balanced chemical equation: $Ba(NO_3)_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaNO_3(aq)$

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A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The balanced chemical equation is:

$Ba(NO_3)_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaNO_3(aq)$

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