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Arada [10]
3 years ago
12

A particle of charge q moving through a magnetic field B experiences the force where v is the velocity of the particle. Show tha

t: (i) The force does no work in moving the particle along its path from t = 0 to t=T. (i1) The speed v(t) Iv(O)ll of the particle is constant in time e particle 1s constant in time
Physics
1 answer:
MrRa [10]3 years ago
3 0

Answer:

       dx/Dt x B . x  =0

Explanation:

Let's calculate the work and the magnetic force, the expression for magnetic force is

        F = qv x B

Bold indicate vector quantities, the expression for the job is

         W = F. X

Let's replace in this equation

       W = q v x B . X

The definition of speed is

      v =  dX / dt

With what work is left

     W = q dX / dt x B . X

As we can see the vector product gives us a vector perpendicular to dX and its scalar product by X of zero

Second part

   The speed a vector and although the magnitude is constant the change of direction implies a change in the speed.

   Let's calculate the magnitudes of speed (speed)

       F = qv B sin θ

       F = ma

       q v B sin θ = ma

       a = qvB / m senT

     

This acceleration is perpendicular to the magnetic field and the velocity, so it does not change if magnitude but its direction, it is directed to the center of the circle.

   | v | = q vB/m sin θ

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Answer:

Angle with the +x axis is θ = 79.599degree

Then the velocity of owner = 1.235m/s

Explanation:

Given that the mass of dog is m1 =26.2 kg

velocity of dog is u1 = 3.02 m/s (north)

mass of cat is m2 = 5.3 kg

velocity is u2 = 2.74 m/s (east )

Mass of owner is M = 65.1 kg

Consider the east direction along +x axis andnorth along +y

momentum of dog is Py = m1 x u1

= 79.124 kg.m/s (j)

momentum of cat is Px = m2 x u2

= 14.522 kg.m/s (i)

Then the net magnitude of momentum is P = (Px2 + Py2)1/2

= 80.445

Angle with the +x axis is θ =tan-1(Py / Px ) = 79.599 degree

Then the velocity of owner is v = P / M = 1.235 m/s

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Explanation:

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where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the work
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A very narrow beam of white light is incident at 40.80° onto the top surface of a rectangular block of flint glass 11.6 cm thick
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Dispersion angle = 0.3875 degrees. 
Width at bottom of block = 0.09297 cm 
Thickness of rainbow = 0.07038 cm 
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 n1*sin(θ1) = n2*sin(θ2)
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 Î¸1, θ2 = angle of incident rays as measured from the normal to the surface. 
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 n1*sin(θ1) = n2*sin(θ2)
 n1*sin(θ1)/n2 = sin(θ2)
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 Red:
 asin(n1*sin(θ1)/n2) = θ2
 asin(1.00029*sin(40.80)/1.641) = θ2
 asin(1.00029*0.653420604/1.641) = θ2
 asin(0.398299876) = θ2
 23.47193844 = θ2 
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 asin(n1*sin(θ1)/n2) = θ2
 asin(1.00029*sin(40.80)/1.667) = θ2
 asin(1.00029*0.653420604/1.667) = θ2
 asin(0.39208764) = θ2
 23.08446098 = θ2 
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 23.47193844 - 23.08446098 = 0.38747746 degrees. 
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 tan(θ) = X/11.6
 11.6*tan(θ) = X
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 11.6*tan(θ) = X
 11.6*tan(23.47193844) = X
 11.6*0.434230136 = X
 5.037069579 = X 
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 11.6*tan(θ) = X
 11.6*tan(23.08446098) = X
 11.6*0.426215635 = X
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 cos(θ) = X/0.092968218
 0.092968218*cos(θ) = X 
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7 0
3 years ago
What is the size of the smallest vertical plane mirror in which a 6 ft tall person standing erect can see her full-length image?
Alex Ar [27]

Answer:

3 ft

..................

5 0
3 years ago
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