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Rainbow [258]
2 years ago
13

How many moles of water will be produced from the combustion of 0.27 moles of CH3OH?

Chemistry
1 answer:
Valentin [98]2 years ago
5 0

Answer:

0.54 mole of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3OH + 3O2 —> 2CO2 + 4H2O

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Finally, we shall determine the number of mole of water (H2O) produced by the reaction of 0.27 moles of CH3OH. This can be obtained as follow:

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Therefore, 0.27 moles of CH3OH will react to produce = (0.27 × 4)/2 = 0.54 mole of H2O.

Thus, 0.54 mole of H2O is produced from the reaction.

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Answer:

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Explanation:

From the question we are told that

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Generally the ionization energy of boron pre atom is mathematically represented as

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Here  N_A is the Avogadro's constant with value N_A  =  6.022*10^{23}

So

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Explanation:

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