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tia_tia [17]
3 years ago
10

An intercontinental ballistic missile goes from rest to a speed of 6.50 km/s in 60.0 s. In multiples of g, what is its accelerat

ion?
Physics
1 answer:
iragen [17]3 years ago
6 0

Answer:

The acceleration is 11.1g\ m/s^2

Explanation:

Given that,

Speed v= 6.50\ km/s=6.5\times10^{-3}\ m/s

Time t = 60.0 sec

We need to calculate the acceleration

Using formula off acceleration

a = \dfrac{\Delta v}{t}

a=\dfrac{v_{f}-v_{i}}{t}

We know that,

Missile goes from rest

So, Initial velocity =0

Put the value into the formula

a =\dfrac{6.50\times10^{3}}{60.0}

a=108.33\ m/s^2

On right hand side multiplying and dividing by g = 9.8m/s²

a=108.33\times\dfrac{g}{g}

Put the value of g

a = \dfrac{108.33}{9.8}g\ m/s^2

a = 11.1g\ m/s^2

Hence, The acceleration is 11.1g\ m/s^2

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The energy band gap of GaAs is 1.4eV. calculate the optimum wavelength of light for photovoltaic generation in a GaAs solar cell
Viktor [21]

Answer:

λ = 8.88 x 10⁻⁷ m = 888 nm

Explanation:

The energy band gap is given as:

Energy Gap = E = 1.4 eV

Converting this to Joules (J)

E = (1.4 eV)(1.6 x 10⁻¹⁹ J/1 eV)

E = 2.24 x 10⁻¹⁹ J

The energy required for photovoltaic generation is given as:

E = hc/λ

where,

h = Plank's Constant = 6.63 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light = ?

Therefore,

2.24 x 10⁻¹⁹ J = (6.63 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/λ

λ = (6.63 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2.24 x 10⁻¹⁹ J)

<u>λ = 8.88 x 10⁻⁷ m = 888 nm</u>

7 0
3 years ago
Consider a uniform electric field of 50 N/C directed toward the east. If the voltage measured relative to ground at a given poin
qaws [65]

Answer:

30 V

Explanation:

Given that:

The uniform electric field = 50 N/C

Voltage = 80 V

distance = 1.0 m

The potential difference of the electric field = Δ V

E_d = V₁ - V₂

50 × 1 = 80V - V₂

50 - 80 V = - V₂

-30 V = - V₂

V₂ = 30 V

5 0
3 years ago
A rectangular loop with dimensions 4.20 cm by 9.50 cm carries current I. The current in the loop produces a magnetic field at th
tiny-mole [99]

Answer:

I=1.48 A

Explanation:

Given that

B=3.1 x 10⁻5 T

b= 4.2 cm

l= 9.5 cm

The relationship for magnetic field  and current given as

B=\dfrac{2\mu _oI}{\pi}D

Where

D=\dfrac{\sqrt{l^2+b^2}}{lb}

By putting the values

D=\dfrac{\sqrt{l^2+b^2}}{lb}

D=\dfrac{\sqrt{0.042^2+0.095^2}}{0.042\times 0.095}

D=26.03 m⁻¹

B=\dfrac{2\mu _oI}{\pi}D

3.1\times 10^{-5}=\dfrac{2\times 4\times \pi \times 10^{-7} I}{\pi}\times 26.03

I=\dfrac{3.1\times 10^{-5}}{{2\times 4\times 10^{-7} }\times 26.03}

I=1.48 A

8 0
3 years ago
What substances were found in the innermost regions (within about the inner 0.3 AUAU) of the solar system before planets began t
julsineya [31]

Answer:

Hydrogen and helium compounds.

Explanation:

We know that the solar System was formed around <u>4.6 billion years ago, </u>due to the gravitational collapse of a giant interstellar molecular cloud.

This cloud  is a type of interstellar cloud and its density and size permit the formation of molecules, most commonly molecular hydrogen.

Therefore the principal substances were found before planets began to form are hydrogen and helium compounds, besides Rocks, metals, most of them in gaseous form.

I hope it helps you!

6 0
3 years ago
J.J. Thomson discovered the electron by noticing that: A. molecules with the same atoms exhibited the same chemical properties.
GenaCL600 [577]

J.J. Thomson discovered the electron by noticing that a beam of particles could be influenced by an electric or magnetic force.. That is option B.

<h3>What is an electron?</h3>

An electron can be defined as the part of an atom that is negatively charged and is found revolving round the nucleus of an atom.

J.J. Thomson was the scientist that discovered electrons through subjecting two oppositely-charged electric plates around the cathode ray.

He noticed that the particles where deflected by both the magnetic and electric fields.

Learn more about cathode rays here:

brainly.com/question/4441361

#SPJ1

4 0
2 years ago
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