Answer:
0.0195 m
Explanation:
= density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³
= diameter of hockey puck = 13 cm = 0.13 m
= height of hockey puck = 2.8 cm = 0.028 m
= density of mercury = 13.6 gcm⁻³ = 13600 kgm³
= depth of puck below surface of mercury
According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck
Weight of mercury displaced = Weight of puck
The answer is D. <span>iron, cobalt, and nickel</span>
Answer:
<em>61.9°</em>
Explanation:
The formula for calculating the workdone is expressed as
Workdone = Fdsin theta
F is the force applied on the crate
d is the distance covered
theta is the angle that the rope makes with the horizontal
Given
F = 40N
d = 7m
Workdone = 247J
Substituting into the formula:
247 = 40(7)sin theta
247 = 280sin theta
sin theta = 247/280
sin theta = 0.88214
theta = arcsin(0.88214)
theta = 61.9°
<em>Hence the angle that the rope makes with the horizontal is 61.9°</em>
Answer: 0.36 m
Explanation:
By definition, the x coordinate of the center of mass of the system obeys the following equation:
Xm = (m1x1 + m2x2 + …….+ mnxn) / m1+m2 +……+ mn
Neglecting the mass of the rod, and choosing our origin to be coincident with the location of the full bucket, we can write the following expression for the X coordinate of the center of mass (Assuming that both masses are aligned over the x-axis, so y-coordinates are zero):
Xm = 0.25 mb . 1.8 m / (1+0.25) mb
Simplifying mb, we get:
Xm= 0.36 m (to the right of the full bucket).