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raketka [301]
3 years ago
7

A package falls from an airplane in level flight at constant speed. If air resistance can be neglected, how does the motion of t

he package look to the pilot
Physics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer: The package appears to fall straight downward

Explanation:

When the package is dropped from the plane (which has constant speed) it will follow a parabolic path. Then, as the plane and the package have the same constant speed in the horizontal component (X component of the movement) and a constant vertical acceleration due gravity, from the plane the package will always be seen below it, falling straight downward (free fall).

This is possible if it is assumed that there are no additional horizontal forces such as air resistance, thus fulfilling Newton's 1st Law of inertia that estates if a body is in equilibrium the sum of all the forces acting on it is equal to zero.

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Answer: the Time that is required is called a period

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If Galileo drops a cannon ball from the 60 meter high) Leaning Tower of Pisa, how fast will it be moving when it hits the ground
viva [34]

Answer:

When the ball hits the ground, the velocity will be -34 m/s.

Explanation:

The height and velocity of the ball at any time can be calculated using the following equations:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height of the ball at time "t".

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v0 = initial velocity.

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g = acceleration due to gravity. (-9.8 m/s² considering the upward direction as positive).

v = velocity at time "t".

If we place the origin of the frame of reference on the ground, when the ball hits the ground its height will be 0. Then using the equation of height, we can calculate the time it takes the ball to reach the ground:

y = y0 + v0 · t + 1/2 · g · t²

0 = 60 m + 0 m/s · t - 1/2 · 9.8 m/s² · t²

0 = 60 m - 4.9 m/s² · t²

-60 m / -4.9 m/s² = t²

t = 3.5 s

Now, with this time, we can calculate the velocity of the ball when it reaches the ground:

v = v0 + g · t

v = 0 m/s - 9.8 m/s² · 3.5 s

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Answer:

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