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raketka [301]
3 years ago
7

A package falls from an airplane in level flight at constant speed. If air resistance can be neglected, how does the motion of t

he package look to the pilot
Physics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer: The package appears to fall straight downward

Explanation:

When the package is dropped from the plane (which has constant speed) it will follow a parabolic path. Then, as the plane and the package have the same constant speed in the horizontal component (X component of the movement) and a constant vertical acceleration due gravity, from the plane the package will always be seen below it, falling straight downward (free fall).

This is possible if it is assumed that there are no additional horizontal forces such as air resistance, thus fulfilling Newton's 1st Law of inertia that estates if a body is in equilibrium the sum of all the forces acting on it is equal to zero.

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A 594 Ω resistor, an uncharged 1.3 μF capacitor, and a 6.53 V emf are connected in series. What is the current in milliamps afte
ivanzaharov [21]

Answer:

6.88 mA

Explanation:

Given:

Resistance, R = 594 Ω

Capacitance = 1.3 μF

emf, V = 6.53 V

Time, t = 1 time constant

Now,

The initial current, I₀ = \frac{\textup{V}}{\textup{R}}

or

I₀ = \frac{\textup{6.53}}{\textup{594}}

or

I₀ = 0.0109 A

also,

I = I_0[1-e^{-\frac{t}{\tau}}]

here,

τ = time constant

e = 2.717

on substituting the respective values, we get

I = 0.0109[1-e^{-\frac{\tau}{\tau}}]

or

I = 0.0109[1-2.717^{-1}]

or

I = 0.00688 A

or

I = 6.88 mA

5 0
3 years ago
What do the law of superposition and the law of inclusion have in common? (1 point) 1. Both laws are about matching fossils in d
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Explanation:

4 0
3 years ago
Determine the capacitive reactance for a 20 uF capacitor that is across a 20 volt, 60 Hz source
aleksandr82 [10.1K]

Answer:

Capacitive reactance is 132.6 Ω.

Explanation:

It is given that,

Capacitance, C=20\ \mu F=20\times 10^{-6}\ F=2\times 10^{-5}\ F

Voltage source, V = 20 volt

Frequency of source, f = 60 Hz

We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :

X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\ Hz\times 2\times 10^{-5}\ F}

X_C=132.6\ \Omega

So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.

4 0
3 years ago
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