<h2>Ur Answer:-</h2>
The cambial ring becomes active and starts cutting off new cells; both on the inner and the outer sides. The cells which are cut off towards the pith mature into secondary xylem. The cells which are cut off towards the periphery mature into secondary phloem.
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Answer:
The correct answer is - B) Elysia Chlorotica grows when exposed to light in the absence of other food sources
Explanation:
If placing Elysia Chlorotica in presence of the food sources in the presence or absence of light it still grows as normal. However, if placing in the light in absence of the food sources it should not grow if it is not able to perform photosynthesis but it does which means there is a photosynthesis process also involve in the Elysia.
Photosynthesis is the process that involves the production of energy and nutrition in presence of light with water and atmospheric carbon dioxide.
Answer:
Ss and ss
Explanation:
<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>
<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>
Now, let us look at a cross between the two parents;
Ss x ss
Progeny: Ss, Ss, ss, ss.
Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.
Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.
Hence, the genotypes of the two parents are Ss and ss.
Answer: Cows put in a pasture of fresh grass will eat it down too a point it would regrow fast.. Unless the pasture is not large enough for the number of cattle. Then they will eat it into the ground and kill it.
Explanation:
