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gizmo_the_mogwai [7]
3 years ago
14

What volume of 0.125 M HCl is needed to titrate 50.0 mL of 0.0500 M NH3 solution ?

Chemistry
1 answer:
Scrat [10]3 years ago
6 0

Answer:

20

Explanation:

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How does mixture relate to life​
masya89 [10]

Answer:

For example, when we bake a cake, it's a result of a mixture of eggs, flour, sugar, and other ingredients.  Any time two or more items are combined, a mixture is formed. Sometimes, the different parts of a mixture can be separated into individual entities. Other times, they're married for as long as they exist.

Explanation:

3 0
3 years ago
What is the pH of a solution with a hydronium concentration of 0.36 M?
kodGreya [7K]

Answer:

<h2>0.44 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H_3O}^{+}]

From the question we have

pH =  -  log(0.36)  \\  = 0.4436...

We have the final answer as

<h3>0.44</h3>

Hope this helps you

8 0
3 years ago
Carbon hexafluroide formula
ikadub [295]

The formula for Hexafluoride is F6S.

4 0
3 years ago
What is the boiling point of a solution produced by adding 610 g of cane sugar (molar mass 342.3 g/mol) to 1.4 kg of water? For
wel

Answer:

Boiling point of solution is 100.65^{0}\textrm{C}

Explanation:

Cane sugar is a non-volatile solute.

According to Raoult's law for a non-volatile solute dissolved in a solution-

                              \Delta T_{b}=K_{b}.m

Where, \Delta T_{b} is elivation in boiling point of solution, K_{b} is ebbulioscopic constant of solvent (how much temperature is raised for dissolution of 1 mol of non-volatile solute) and m is molality of solution.

Here, K_{b}=0.51^{0}\textrm{C}.kg.mol^{-1}

610 g of cane sugar = \frac{610}{342.3} moles of cane sugar

                                  = 1.78 moles of cane sugar

So, molality of solution (m) = \frac{1.78}{1.4}mol.kg^{-1}=1.27mol.kg^{-1}

Plug in all the values in the above equation, we get-

\Delta T_{b}=0.51^{0}\textrm{C}.kg.mol^{-1}\times 1.27mol.kg^{-1}=0.65^{0}\textrm{C}

So, boiling point of solution = (100+0.65)^{0}\textrm{C}=100.65^{0}\textrm{C}              

7 0
3 years ago
What is the total mass of the reactants in the equation below?
Keith_Richards [23]

Answer:

266.7 g

Explanation:

Molar mass of AlCl3=133.3405 g

2AlCl3=2×133.34

          =266.7 g

Please mark brainliest

4 0
3 years ago
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