Which are strong bases? Check all that apply. HCI NaOH NH3 H2CO3 ΠΗΝΟΣ OKOH

A soccer ball is kicked with a speed of 22m/s at an angle of 35.0º above the horizontal. If the ball lands at the same level fro

Lisa [10]

Answer:

2.57 seconds

Explanation:

The motion of the ball on the two axis is;

x(t) = Vo Cos θt

y(t) = h + Vo sin θt - 1/2gt²

Where; h is the initial height from which the ball was thrown.

Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²

We want to find the time t at which y(t) = h

Therefore;

y(t) = h + Vo sin θt - 1/2gt²

Whose solutions are, t = 0, at the beginning of the motion, and

t = 2 Vo sinθ/g

= (2 × 22 × sin 35°)/9.81

= 2.57 seconds

6 0

3 years ago

Individual sports are different from team sports in that they require an internal focus and dialogue. Please select the best ans

inessss [21]

Answer:

true

Explanation:

It is true that individual sports is different from team sports.

Individual sports depend upon the individual's hard work, focus,determination only he is responsible for his fate.

when we talk about team sports it is about co-ordination , team brilliance individual cannot team sport alone every one have to contribute for the team to succeed.

6 0

3 years ago

PLEASE HELP ME IN THIS QUESTION!!!

kirill115 [55]

Answer:

Acceleration is 8.45 and the tension is 2.775

Explanation:

Lets apply the equation F=ma for vertical block,

5-T= 0.5a

foe the frictional force acting on the object,

f=0.11×5 (consider equation no.1)

=0.55N

Applying F=ma for the block which is on surface,

T-0.55=0.5a (consider as equation no.2)

no.1=no.2

5.55=2T

T=2.775

by equation no.1,

4.225=0.5a

a=8.45

8 0

3 years ago

Duplain st. is 300m long and runs from west to east between Baron and Burkey. If keith is strolling east from Baron at an averag

nadezda [96]

Answer:

Time, t = 2 minutes

Explanation:

Given that,

Length of Duplain st. d = 300 m = 0.3 km

If keith is strolling east from Baron at an average velocity of, v = 3 km/hr

Sue is power-walking west from Burkey at an average velocity of, v' = 6 km/hr

To find,

How long will it take them to meet ?

Solution,

When both objects are travelling in opposite direction, then the total speed is given by :

V = v + v'

V = 3 km/hr + 6 km/hr

V = 9 km/hr

Let t is the time taken will it take them to meet. It can be calculated as :

$t=\dfrac{d}{V}$

$t=\dfrac{0.3\ km}{9\ km/hr}$

t = 0.033 hour

or

t = 1.98 minutes

i.e. t = 2 minutes

So, they will take 2 minutes to meet. Hence, this is the required solution.

4 0

4 years ago

Suppose that you have a spring gun that you use to launch a small metal ball. You try the first two settings of the gun. The fir

Ivan

Answer:

The distance s of how far the ball will go at the highest setting = 2.25m

Explanation:

Let consider x to be the representative of the compression and the distance to be s

Recall that:

$\dfrac{1}{2}\times K \times x^2 = mgs +c$

By cross multiplying

$K \times x^2 = 2(mgs +c)$

$K \times x^2 = 2\times 9.81(ms) +2c$

$K \times x^2 = 19.62(ms) +2c$

$x^2 = A \times s+B$

Thus, for the first setting

x = 1 , s = 0.25

for the second setting

x = 2, s = 1

1 = 0.25A + B --- (1)

4 = A + B ----- (2)

From (1); let B = 1 - 0.25A and substitute it into (2)

4 = A + 1 - 0.25 A

4 - 1 = A - 0.25 A

3 = 0.75 A

A = 3/0.75

A = 4

From (2)

4 = A + B

4 = 4 + B

B = 4 - 4

B = 0

Therefore, for the highest setting, where x = 3

Then :

$x^2 = A \times s+B$ will be:

3² = 4s + 0

9 = 4s

s = 9/4

s = 2.25 m

∴

The distance s of how far the ball will go at the highest setting = 2.25m

6 0

4 years ago