Answer:
Available usage time for the computer = 10.185 hrs
Explanation:
for the dryer;
I = 15 A, V=240 V , t= 55min,
convert time from min to sec. t = 55*60 =3300 sec
Energy = IVt
Energy = 15*240*3300
Energy = 11,880,000 J
=11,800 KJ
using the energy for the clothes dryer to calculate for the time spent on the computer,
Energy = IVt
for the computer;
I = 2.7A V=120V , t=?
t=36,666.7sec
convert this value to hour by dividing by 3600
Coulomb's Law
Given:
F = 3.0 x 10^-3 Newton
d = 6.0 x 10^2 meters
Q1 = 3.3x 10^-8 Coulombs
k = 9.0 x 10^9 Newton*m^2/Coulombs^2
Required:
Q2 =?
Formula:
F = k • Q1 • Q2 / d²
Solution:
So, to solve for Q2
Q2 = F • d²/ k • Q1
Q2 = (3.0 x 10^-3 Newton) • (6.0 x 10^2 m)² / (9.0 x 10^9
Newton*m²/Coulombs²) • (3.3x 10^-8 Coulombs)
Q2 = (3.0 x 10^-3 Newton) • (360 000 m²) / (297 Newton*m²/Coulombs)
Q2 = 1080 Newton*m²/ (297 Newton*m²/Coulombs)
Then, take the reciprocal of the denominator and start
multiplying
Q2 = 1080 • 1 Coulombs/297
Q2 = 1080 Coulombs / 297
Q2 = 3.63636363636 Coulombs
Q2 = 3.64 Coulumbs
Answer:
Work
Explanation:
The use of force to move an object is the definition of "work" in physics.
The force needed to overcome sliding friction is more than the force needed to overcome rolling friction or static or even fluid
