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timofeeve [1]
3 years ago
13

What is the charge of a beta particle?

Chemistry
2 answers:
Delvig [45]3 years ago
7 0

Answer:

Beta particles have a charge of minus 1.

Explanation:

Hope this helps!

miv72 [106K]3 years ago
4 0

Answer:

<em><u>MARK AS BRAINLIEST ANSWER</u></em>

<em><u>PLZ FOLLOW ME</u></em>

Explanation:

Beta particles have a mass which is half of one thousandth of the mass of a proton and carry either a single negative (electron) or positive (positron) charge. As they have a small mass and can be released with high energy, they can reach relativistic speeds (close to the speed of light)

HOPE IT HELPS YOU

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Explanation:

Inspite of having similar intermolecular forces, CS2 has a higher boiling point than CO2, since it has a greater molar mass. The potential energy of molecules reduces until a certain level as they get closer to each other. Although the polarity of both CO2 and CS2 are cancelled because of their linear structure.

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3 years ago
A scientist wants to perform a controlled experiment to test the effect of rust on chemically treated iron. which action would b
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6) What is located in the nucleus?
jek_recluse [69]

Answer:

Protons and Neutrons are found in the nucleus

7 0
4 years ago
A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
Romashka [77]

Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (  27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

7 0
3 years ago
Convert the following masses into kilograms:
beks73 [17]

Answer:

(a): 2,300 kilograms

(b): 0.005 kilograms

(c): 2.3 × 10^-5 kilograms

(d): 155 kilograms

Explanation:

Formulas:

(a); divide the mass value by 1000

(b); divide the mass value by 1e+6

(c); divide the mass value by 1e+9

(d); multiply the mass value by 1000

5 0
3 years ago
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