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sasho [114]
3 years ago
12

The distance from Santa Maria to Los Alamos is 16.25 mi. what is the distance in meters?

Chemistry
1 answer:
Radda [10]3 years ago
7 0

Answer:

26,167.47m

Explanation:

Problem:

We are to solve this problem using dimensional analysis:

  from the given conversion factors-

      0.621mi = 1.00km

       1km = 1000m

From the problem, we are groing from miles to metres:

      16.25mi x \frac{1km}{0.621mi} x \frac{1000m}{1km}

The mi will cancel out and also the km. This leaves us with the desired unit we want which is meters, m.

       =  26,167.47m

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Which of these structures is least in danger of chemical weathering?
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Answer: a bench made of composite plastic

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3 years ago
What mass of water in grams will fill a tank 126cm long, 47 cm wide, and 13 cm high
Shtirlitz [24]

Answer:

Mass =  76986  g

Explanation:

Given data:

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Volume = length ×height ×width

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8 0
3 years ago
Calculate ΔHrxn for the following reaction: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/
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Answer:

The answer to your question is:  ΔHrxm = -23.9 kJ

Explanation:

Data:

2Fe(s)+3/2O2(g)→Fe2O3(s),  ΔH = -824.2 kJ     (1)

    CO(g)+1/2O2(g)→CO2(g)         ΔH = -282.7 kJ   (2)

Reaction:

                          Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)  

We invert (1) and change the sign of  ΔH

        Fe2O3(s)   →  2Fe(s)+3/2O2(g)  ΔH = 824.2 kJ

We multiply (2) by 3

      3(  CO(g)+1/2O2(g)→CO2(g)         ΔH = -282.7 kJ)   (2)

      3CO(g)+3/2O2(g)→3CO2(g)         ΔH = -848.1 kJ

We add (1) and (2)

Fe2O3(s)   →  2Fe(s)+3/2O2(g)  ΔH = 824.2 kJ

3CO(g)+3/2O2(g)→3CO2(g)         ΔH = -848.1 kJ

Fe2O3(s) +  3CO(g)+3/2O2(g)  →  2Fe(s)+3/2O2 + 3CO2(g)    

Simplify

    Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)    and ΔHrxm = -23.9 kJ

6 0
3 years ago
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