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Lena [83]
3 years ago
13

2. What is forensic odontology ? Why is this area helpful for investigators?

Chemistry
2 answers:
Rom4ik [11]3 years ago
6 0

Answer:

Also called forensic dentists, forensic odontologists are typically called in to: Identify human remains that cannot be identified using face recognition, fingerprints or other means. Identify bodies in mass fatalities, such as plane crashes and natural disasters. This area is helpful for investigators as it helps find more evidence for each case.

horrorfan [7]3 years ago
4 0

Explanation:

forensic odontology is the study of dental applications in legal proceedings. which may include bite marks.

it is helpful as it allows for the identification of unknown bodies through dental records.

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4.00 moles of sodium has a mass of 91.96 grams.

To find an element's molar mass, you can use its atomic weight.

8 0
3 years ago
what method can be used to seperate parts of liquid mixture wwhen the entire mixture can pass through a filter
QveST [7]
Distillation is the <span>method that can be used to seperate parts of liquid mixture when the entire mixture can pass through a filter.</span>
6 0
3 years ago
How much pure acid is in 520 milliliters of a 13 ​% ​solution?
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It actually depends on the percentage of the concentration give. Percentages can be expressed as %mass/mass, %volume/volume or %mass/volume. To keep things simple, let's just assume that it is in %volume/volume. Thus, 13% of 520 mL is pure acid.

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What is an Atom?<br><br> What are the 5 most common elements that make up the human body?.
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6 0
3 years ago
The theoretical yield of a reaction is the amount of product obtained if the limiting reactant is completely converted to produc
Elis [28]

Answer: 9.9 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{8.150g}{2g/mol}=4.08moles

b) moles of C_2H_4

\text{Number of moles}=\frac{9.330g}{28g/mol}=0.33moles

H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)

According to stoichiometry :

1 mole of C_2H_4 combine with 1 mole of H_2

Thus 0.33 mole of C_2H_4 will combine with =\frac{1}{1}\times 0.33=0.33 mole of H_2

Thus C_2H_4 is the limiting reagent as it limits the formation of product.

As 1 mole of C_2H_4 give =  1 mole of C_2H_6

Thus 0.33 moles of C_2H_4 give =\frac{1}{1}\times 0.33=0.33moles  of C_2H_6

Mass of C_2H_6=moles\times {\text {Molar mass}}=0.33moles\times 30g/mol=9.9g

Thus theoretical yield (g) of C_2H_6 produced by the reaction is 9.9 grams

7 0
3 years ago
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