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Alexxandr [17]
3 years ago
13

What mass of sulfur must be used to produce 17.5 L of gaseous sulfur dioxide at STP according to the following equation?

Chemistry
1 answer:
Greeley [361]3 years ago
3 0

Answer:

                     25.05 g of S₈

Explanation:

                     The balance chemical equation for given synthetic reaction is,

                                            S₈ + 8 O₂ → 8 SO₂

Step 1: <u>Calculate Moles of SO₂ at STP:</u>

According to Avogadro's Law, at STP (0 ° C and 1 atm) every ideal gas occupies 22.4 L of volume.  Therefore, the moles contained by 17.5 L of SO₂ are as;

                             Moles  =  17.5 L / 22.4 L

                             Moles  =  0.781 moles of SO₂

Step 2: <u>Calculate Moles of S₈ consumed:</u>

According to balance equation,

8 moles of SO₂ were produced by  =  1 mole of S₈

So,

0.781 moles of SO₂ will be produced by  =  X moles of S₈

Solving for X,

                      X  =  0.781 mol × 1 mol / 8 mol

                      X  =  0.0976 moles of S₈

Step 3: <u>Calculate Mass of S₈ as;</u>

                      Mass  =  Moles × M.Mass

                      Mass  =  0.0976 mol × 256.52 g/mol

                      Mass =  25.05 g of S₈

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Oliver needs to standardize a base solution by titration with an acid solution of known concentration. He finds the volume of th
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2 years ago
How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?
vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

7 0
3 years ago
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