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2 years ago

When bismuth-212 undergoes alpha decay, it becomes which of the following?

Chemistry

2 answers:

Iteru [2.4K]2 years ago

8 0

Answer: -

When bismuth-212 undergoes alpha decay, it becomes ²⁰⁸Tl

Explanation: -

Mass number of ²¹²Bi = 212

Atomic number of ²¹²Bi = 83

When alpha decay occurs the mass number decreases by 4 and the atomic number decreases by 2.

Mass number of daughter = 212 - 4 = 208

Atomic number of daughter = 83 - 2 = 81

It is the atomic number of Thallium Tl.

Thus the daughter nucleide is ²⁰⁸Tl.

lana [24]2 years ago

8 0

Answer:

Thallium-208 + and alpha particle

Explanation:

Atomic number of Bismuth-212 is 83. The resulting nucleus after the emission of alpha particle has mass number 208 and atomic number 81. Atomic number 81 corresponds to Thallium-208.

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Table salt is also known as sodium chloride, because it is

Mnenie [13.5K]

Sodom chloride is an ionic compound.

<h3>What is sodium chloride?</h3>

Sodium chloride is a compound that is formed by the combination of sodium and chlorine atoms. The compound is ionic as the ions of the atoms combine. Sodium looses one electron that can now be gained by chlorine.

Since the compound is ionic, it has a high melting and boiling point. This implies that the compound could melt as high as 801 degrees centigrade. The boiling point of the compound is much higher.

We can represent the compound using the ball and stick or the space filling model. The ball and stick model of sodium chloride has been shown in the image attached to this answer.

Learn more about ball and stick model:brainly.com/question/17217225

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6 0

1 year ago

Which statement about AHf is true?

Pachacha [2.7K]

Answer:

It is positive when the bonds of the product store more energy than those of the reactants.

Explanation:

The standard enthalpy of formation, ΔHf, is defined as the energy required to form 1 mole of a substance from its contituent elements under standard conditions of pressure and temperature.

Then, per defintion, when the elements are already at their standard states, there is not energy involved to form them from that very state; this is, the standard enthalpy of formation of the elements in their standard states is zero.

It is not zero for the compounds in its standard state, because energy should be released or absorbed to form the compounds from their consituent elements. Thus, the first choice is false.

When the bonds of the products store more energy than the those of the reactants, the difference is:

ΔHf = ΔHf products - ΔHf reactants > 0, meaning that ΔHf is positive. Hence, the second statement is true.

Third is false because forming the compounds may require to use (absorb) or release (produce) energy, which means that ΔHf could be positive or negative.

Fourth statement is false, because the standard state of many elements is not liquid. For example, it is required to supply energy to iron to make it liquid. Thus, the enthalpy of formation of iron in liquid state is not zero.

3 0

3 years ago

Find the volume of a gas if 3.6 mols of the gas is at STP

Digiron [165]

Answer:

81 L gas

General Formulas and Concepts:

Ideal Gas Law

STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 3.6 mols gas at STP

[Solve] volume (L) of gas

Step 2: Convert

[DA] Set up: $\displaystyle 3.6 \ mol \ gas(\frac{22.4 \ L \ gas}{1 \ mol \ gas \ at \ STP})$
[DA] Multiply [Cancel out units]: $\displaystyle 80.64 \ L \ gas$

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs.

80.64 L gas ≈ 81 L gas

6 0

3 years ago

An element has five isotopes. Calculate the atomic mass of this element using the information below. Show all your work. Using t

Katena32 [7]

Answer: Sol:-

Data provided in the question is :-

Atomic mass of isotope -1 = 64 amu

Atomic mass of isotope -2 = 66 amu

Atomic mass of isotope -3 = 67 amu

Atomic mass of isotope -4 = 68 amu

Atomic mass of isotope - 5 = 70 amu

Percentage abundace of isotope - 1 = 48.89 %

Percentage abundance of isotope -2 = 27.81 %

Percentage abundance of isotope - 3 = 4.11%

Percentage abundance of isotope-4 = 18.57%

Percentage abundance of isotope - 5 = 0.62 %

Formula used :-

Average atomic mass of an element =[ {(atomic mass of isotope-1 * percentage abundance of isotope-1) + ( atomic mass of isotope-2 * percentage abundance of isotope -2) + ( atomic mass of isotope -3 * percantege abundance of isotope-3 ) + ( atomic mass of isotope-4 * percentage abundance of isotope-4) + (atomic mass of isotope-5 * percentage abundance of isotope-5)} / 100]

Calculation :-

Put all the value in the formula :-

Average atomic mass of an element = [{(64 * 48.89) + (66 * 27.81) + (67 * 4.11) + (68 * 18.57) + (70 * 0.62)} / 100] amu

= [{(3128.96) + (1835.46) +(257.37) + (1262.76) + (43.4)} / 100] amu

= {(6528.04) / 100} amu

= 65.2804 amu

Average atomic mass of an element is = 65.2804 amu

Then this mass is approximatly equal to atomic mass of zinc so this element would be zinc

atomic mass of zinc = 65.38 \approx 65.2804 amu

5 0

2 years ago

Solve for x, where M is molar and s is seconds. x=(5.3×103M−2s−1)(0.26M)3

GREYUIT [131]

Answer:

guys can u solve my ques plz

4 0

2 years ago