Answer:
The baking soda
Explanation:
This is the more reactive part of the experiment. The more baking soda there is (compared to the vinegar), the stronger the reaction.
The density of the liquid is 0.98 g/mL
<h3>What is density? </h3>
The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:
Density = mass / volume
With the above formula, we can obtain the density of the liquid.
<h3>How to determine the density </h3>
- Mass = 30.8 g
- Volume = 31.5 mL
- Density =?
Density = mass / volume
Density of liquid = 30.8 / 31.5
Density of liquid = 0.98 g/mL
Learn more about density:
brainly.com/question/952755
Water has the special type of attraction called Hydrogen bonding. The bonds between the Hydrogen and the Oxygen in each water molecule make a super dipole because the Oxygen atom is way more electronegative than the hydrogen atom. These OH bonds can then be attracted to other H2O molecules. If you have ever poured water up to the brim and there is little bit of water that is poking above the top, hydrogen bonding keeps those water molecules from spilling
<u>Answer:</u> The mass of water that should be added in 203.07 grams
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:

Where,
m = molality of barium iodide solution = 0.175 m
= Given mass of solute (barium iodide) = 13.9 g
= Molar mass of solute (barium iodide) = 391.14 g/mol
= Mass of solvent (water) = ? g
Putting values in above equation, we get:

Hence, the mass of water that should be added in 203.07 grams
Answer:
(a) Polarity of phase: 1. Stationary phase is polar
b) Eluent strength of solvent: 1. Increases as solvent becomes more polar
c) Nature of solutes.1. Polar
d) Nature of solute interaction:2. More soluble in mobile phase as the polarity of the mobile phase decreases
e) Polarity of phases: 1. Stationary phase is polar
f) Eluent strength of solvent: 1. Increases as solvent becomes more polar.
g) Nature of solutes: 1. Polar
h) Nature of solute interaction: 2. More soluble in mobile phase as the polarity of the mobile
Explanation: