Question

When bismuth-212 undergoes alpha decay, it becomes which of the following?

Answer 1

Answer: -

When bismuth-212 undergoes alpha decay, it becomes ²⁰⁸Tl

Explanation: -

Mass number of ²¹²Bi = 212

Atomic number of ²¹²Bi = 83

When alpha decay occurs the mass number decreases by 4 and the atomic number decreases by 2.

Mass number of daughter = 212 - 4 = 208

Atomic number of daughter = 83 - 2 = 81

It is the atomic number of Thallium Tl.

Thus the daughter nucleide is ²⁰⁸Tl.

Answer 2

Answer:

Thallium-208 + and alpha particle

Explanation:

Atomic number of Bismuth-212 is 83. The resulting nucleus after the emission of alpha particle has mass number 208 and atomic number 81. Atomic number 81 corresponds to Thallium-208.