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abruzzese [7]
3 years ago
7

I really need help. The question is what is the length of the line?​

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0

Answer:B.

Step-by-step explanation:

vovikov84 [41]3 years ago
7 0
5. You’re right! :)
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Anyone got an answer <br><br>also it doesn't gimme the option of making this 5pts :(
Shtirlitz [24]

Answer:

Step-by-step explanation:

Each of the squares has trinomials that factor. x^2 - 14x + 49 = (x - 7)^2

When you take the square root (to get the side length) you get x - 7. So the length of each square is x - 7) = 0;..........x=7 That's the answer to a.

The answer to b is the same. The width =7

It's a square both sides have to be equal.  

The length of the rectangle when the two squares are put together is 7 +7 = 14.

Answer: Question a = 7..... Question b = 7 ......... Question C = 14

8 0
3 years ago
Need help with this problem can any help me please iam confused what to do
Vanyuwa [196]
You have to find X and RT by using SU as the median
Explanation: To find the median you have to list the number from least to greatest. Then the middle number is the median. Once you find the median substitute it for X.
5 0
2 years ago
What is |-6,035| ?<br> Plz help
cluponka [151]
The absolute value is the distance between a number and zero. The distance between
-6035 and 0 is 6035
8 0
3 years ago
Read 2 more answers
If ln(4x+y)=2x-3,then dy/dx=
Viktor [21]

\ln(4x+y)=2x-3

Differentiate both sides wrt x:

\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}

By the chain rule, we get

\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2

\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2

Solve for \frac{\mathrm dy}{\mathrm dx}:

4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y

\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}

4 0
3 years ago
What is the measure of each side of a square with area equals 225square meter?
I am Lyosha [343]
It is 15 meters long on each side.
You find the square root of 225 which is 15, because when you multiply 15 by 15 you get 225.
6 0
3 years ago
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