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3 years ago

5

A steel ball bearing is released from a height H and

1 answer:

ArbitrLikvidat [17]3 years ago

4 0

Answer:

ELASTIC collision

kinetic energy is conservate

Explanation:

As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.

As the floor does not move the conservation of the moment

po = pf

-mv1 = m v2

- v1 = v2

So the speed with which it descends is equal to the speed with which it rises

Therefore the kinetic energy of the ball before and after the collision is the same

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A hollow cylinder with an inner radius of and an outer radius of conducts a 3.0-A current flowing parallel to the axis of the cy

Artemon [7]

Complete Question:

A hollow cylinder with an inner radius of 4.0mm and an outer radius of 30mm conducts a 3.0-A current flowing parallel to the axis of the cylinder. If the current density is uniform throughout the wire, what is the magnitude of the magnetic field at a point 12mm from its center?

Answer:

The magnitude of the magnetic field = 7.24 μT

Explanation:

Inner radius, a = 4.0 mm = 0.004 m

Outer radius, b = 30 mm = 0.03 m

Radius, r = 12 mm = 0.012 m

let h² = b² - a²

h² = 0.03² - 0.004²

h² = 0.000884

Let d² = r² - a²

d² = 0.012² - 0.004²

d² = 0.000128

Current I = 3A

μ = 4π * 10⁻⁷

The magnitude of the magnetic field is given by:

$B = \frac{\mu I d^{2} }{2\pi r h^{2} } \\B = \frac{4\pi * 10^{-7} * 3* 0.000128^{2} }{2\pi *0.012* 0.000884^{2} }$

B = 7.24 * 10⁻⁶T

B = 7.24 μT

7 0

3 years ago

an ice skater starts with a velocity of 2.25 m/s in a 50.0 direction. after 8.33 m/s in a 120 direction. what is the y-component

Nata [24]

The y-component of the acceleration is $0.28 m/s^2$

Explanation:

The y-component of the ice skater acceleration can be calculated with the equation

$a_y = \frac{v_y-u_y}{t}$

where

$v_y$ is the y-component of the final velocity

$u_y$ is the y-component of the initial velocity

t is the time elapsed

Here we have:

Initial velocity is $u=2.25 m/s$ at $\theta_1=50.0^{\circ}$ , so its y-component is $u_y = u sin \theta_1 = (2.25)(sin 50.0^{\circ})=1.72 m/s$

Final velocity is $v=4.65 m/s$ at $\theta_2=120.0^{\circ}$ , so its y-component is $v_y = v sin \theta_2 = (4.65)(sin 120.0^{\circ})=4.03 m/s$

The time elapsed is

t = 8.33 s

Therefore, the y-component of the acceleration is

$a_y = \frac{4.03-1.72}{8.33}=0.28 m/s^2$

Learn more about acceleration:

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brainly.com/question/2562700

#LearnwithBrainly

7 0

3 years ago

A solid sphere rolls without slipping down an incline, starting from rest. At the same time, a box starts from rest at the same

NISA [10]

Answer:

The box arrives first.

Explanation:

Hope this helps!! :))

Learn more at :

brainly.com/question/20164917

4 0

2 years ago

Answer me nowwwwwwww

qwelly [4]

Answer:

volume

Explanation:

it depends on the volume of the items

hope this helps

8 0

3 years ago

Read 2 more answers

Two positive charge spheres, the spheres are separated by 0.40 m. The charge on the first sphere is 100 microcoulombs and the

agasfer [191]

Answer: 168.75 N

Explanation:

first, let's convert microcoulombs to coulombs

q1 = 1e-4 C

q2 = 3e-5 C

r = 0.4 m

then use the equation Fe = $\frac{kq_{1} q_{2}}{r^{2} }$

plug in values --> F = (9e9*1e-4*3e-5)/(0.4)^2

F = 168.75 N

8 0

1 year ago