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pochemuha
3 years ago
13

What mass of C6H8O7 should be used every 7.0 X 10^2mg NaHCO3

Chemistry
1 answer:
Savatey [412]3 years ago
4 0

Mass C₆H₈O₇ : 0.531484 g

<h3>Further explanation</h3>

Reaction

3NaHCO₃ (aq) + C₆H₈O₇ (aq) → 3 CO₂ (g) + 3 H₂O (l) + Na₃C₆H₅O₇ (aq)

MW NaHCO₃ : 84 g/mol

mass NaHCO₃ : 7.10² mg=0.7 g

mol NaHCO₃ :

\tt mol=\dfrac{0.7}{84}=0.0083

mol C₆H₈O₇ :

\tt \dfrac{1}{3}\times 0.0083=0.00277

MW C₆H₈O₇ : 192 g/mol

mass C₆H₈O₇ :

\tt mass=0.00277\times 192=0.53184

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Why is the energy supplied by the cooker greater than that calculated ?
TEA [102]

Answer:

Explanation:

Q1.

(a) 46 200

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allow 1 mark for correct substitution

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2

(b) Energy is used to heat the kettle.

[3]

Q2.

(a) (approximate same size particles as each other and as liquid and gas) touching

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Q3.

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Page 12 of 13

points plotted correctly

allow 5 correctly plotted for 2 marks, 3−4

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allow ± ½ square

2

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(b)

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an answer of 0.075 (°C/s) scores 2 marks

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[10]

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Page 13 of 13

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7 0
3 years ago
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sergeinik [125]

Answer:

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Solution:

Data Given;

                  Mass  =  55 g

                  Density  =  0.784 g.cm⁻³

Required:

                  Volume  =  ?

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Solving for Volume,

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Putting values,

                  Volume  =  55 g ÷ 0.784 g.cm⁻³

                  Volume = 70.15 cm³

5 0
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