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3 years ago

What kind of solid tends to have the lowest melting points?

Chemistry

1 answer:

pishuonlain [190]3 years ago

6 0

Answer:

Molecular solids

Covalent compounds

Explanation:

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When an ionic bond forms between lithium (Li) and fluorine (F), which of the following occurs?

allochka39001 [22]

They don't share and both deal with only 1 electron.

Lithium gives away 1 electron.
F will receive that electron.

The chemical formula is LiF

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3 years ago

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If you start with 1.000 gram sample of the isotope how much time would pass before you have just 0.100 grams of the isotope left

Vadim26 [7]

Answer:

So, you're dealing with a sample of cobalt-60. You know that cobalt-60 has a nuclear half-life of

5.30

years, and are interested in finding how many grams of the sample would remain after

1.00

year and

10.0

years, respectively.

A radioactive isotope's half-life tells you how much time is needed for an initial sample to be halved.

If you start with an initial sample

, then you can say that you will be left with

→

after one half-life passes;

⋅

→

after two half-lives pass;

⋅

→

after three half-lives pass;

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→

after four half-lives pass;

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Explanation:

now i know the answer

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3 years ago

A sample of granite contains various oxides of silicon, aluminum, sodium, potassium, calcium, and iron. each of these oxides giv

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It would have a solubility substance and surface

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3 years ago

What are the costs and costs<br> of using door mat

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3 years ago

Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What i

g100num [7]

It's simple, just follow my steps.

1º - in 1 L we have $0.0100~g$ of $BaCO_3$

2º - let's find the number of moles.

$\eta=\frac{m}{MM}$

$\eta=\frac{0.0100}{197.3}$

$\boxed{\boxed{\eta=5.07\times10^{-5}~mol}}$

3º - The concentration will be

$C=5.07\times10^{-5}~mol/L$

But we have this reaction

$BaCO_3\rightleftharpoons Ba^{2+}+CO_3^{2-}$

This concentration will be the concentration of $Ba^{2+}~~and~~CO_3^{2-}$

$K_{sp}=\frac{[Ba^{2+}][CO_3^{2-}]}{[BaCO_3]}$

considering $[BaCO_3]=1~mol/L$

$K_{sp}=[Ba^{2+}][CO_3^{2-}]$

and

$[Ba^{2+}]=[CO_3^{2-}]=5.07\times10^{-5}~mol/L$

We can replace it

$K_{sp}=(5.07\times10^{-5})*(5.07\times10^{-5})$

$K_{sp}\approx25.70\times10^{-10}$

Therefore the $K_{sp}$ is:

$\boxed{\boxed{\boxed{K_{sp}\approx2.57\times10^{-11}}}}$

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4 years ago

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