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3 years ago

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What is the difference between torque and the moment of a force

1 answer:

STatiana [176]3 years ago

3 0

Answer:

Torque Of a Force: If The Force has tendency or Bends The Body about Longitudinal axis of the Body it is Torque. Moment Of a Force :If Force has Tendency to or Rotates the Body about Transverse asis the Body It is Moment .

Explanation:

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Using the equation for the final velocity in terms of masses and initial velocity of the gliders for a perfectly inelastic colli

tatuchka [14]

Answer:

Comparison has been made.

Explanation:

Consider perfectly inelastic collision.Two masses of m1 and m2 with initial velocities u1 and u2 before colliding, stick together after collision and move with common speed v. then according to the rule of momentum preservation

m1u1+m2u2= (m1+m2)v

$v= \frac{m1u1+m2u2}{m1+m2}$

If u1 and u2 are known the final common velocity can be determined

Initial kinetic energy is

$\frac{1}{2}m1u1^{2}+\frac{1}{2}m2u2^{2}$

The collion here is perfectly inelastic this means kinectic energy is not conserved. Therefore, initial kinectic energy is not equal to final kinectic.

$\frac{1}{2}m1v^{2}+\frac{1}{2}m2v^{2}$

4 0

3 years ago

What is the net worth of a car moving 30 miles per hour

miss Akunina [59]

Do you know the mass of the car?

6 0

3 years ago

What happens to the current in a circuit when the resistance is increased

VikaD [51]

then the current will decrease.

hope this helps :)

5 0

3 years ago

The electric field 2.5 mm from a uniform sheet of charge is σ=800, NC. How much charge is contained in a 5.0x5.0 cm section of t

slamgirl [31]

Answer:

The charge is $2.75\times10^{-13}\ C$

Explanation:

Given that,

Distance = 2.5 mm

Electric field = 800 NC

Length $L=5.0\times5.0\times10^{-4}\ m$

We need to calculate the linear charge density

Using formula of linear charge density

$E=\dfrac{2k\lambda}{r}$

$\lambda=\dfrac{Er}{2k}$

Put the value into the formula

$\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}$

$\lambda=1.1\times10^{-10}\ C/m$

We need to calculate the charge

Using formula of charge

$Q=\lambda\timesL$

Put the value into the formula

$Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})$

$Q=2.75\times10^{-13}\ C$

Hence, The charge is $2.75\times10^{-13}\ C$

5 0

3 years ago

A hot-air balloon and its basket are accelerating upward at 0.265 m/s2, propelled by a net upward force of 688 N. A rope of negl

Sergeu [11.5K]

Question:<em> </em><em>Find, separately, them mass of the balloon and the basket (incidentally, most of the balloon's mass is air)</em>

Answer:

The mass of the balloon is 2295 kg, and the mass of the basket is 301 kg.

Explanation:

Let us call the mass of the balloon $m_1$ and the mass of the basket $m_2$ , then according to newton's second law:

$(1). \:F = (m_1+m_2)a$ ,

where $a =0.265m/s^2$ is the upward acceleration, and $F = 688N$ is the net propelling force (counts the gravitational force).

Also, the tension $T$ in the rope is 79.8 N more than the basket's weight; therefore,

$(2). \:T = m_2g+79.8$

and this tension must equal

$T -m_2g =m_2a$

$(3). \:T = m_2g +m_2a$

Combining equations (2) and (3) we get:

$m_2a = 79.8$

since $a =0.265m/s^2$ , we have

$\boxed{m_2 = 301.13kg}$

Putting this into equation (1) and substituting the numerical values of $F$ and $a$ , we get:

$688N = (m_1+301.13kg)(0.265m/s^2)$

$\boxed{m_1 = 2295 kg}$

Thus, the mass of the balloon and the basket is 2295 kg and 301 kg respectively.

8 0

3 years ago