Answer:
#_photon = 5 10²⁰ photons / s
Explanation:
For this exercise let's calculate the energy of a single quantum of energy, use Planck's law
E = h f
c= λ f
E = h c / λ
λ= 1000 nm (1 m / 109 nm) = 1000 10⁻⁹ m
Let's calculate
E₀ = 6.6310⁻³⁴ 3 10⁸/1000 10⁻⁹
E₀ = 19.89 10⁻²⁰ J
This is the energy emitted by a photon let's use a proportions rule to find the number emitted in P = 100 w
#_photon = P / E₀
#_photon = 100 / 19.89 10⁻²⁰
#_photon = 5 10²⁰ photons / s
Answer
given,
gauge pressure = 1.94 x 10⁵ Pa
Pressure due to 4.90 m column of water
= ρ g h
= (4.90) x (1000) x (9.8) Pa
= 48020 Pa
Gauge pressure of second floor faucet
= 1.94 x 10⁵Pa - 48020 Pa
P_g= 145980 Pa
( b )
Let h = height of faucet from which no water can flow even if open
P = ρ g h
1.94 x 10⁵ = h x(1000) x (9.8)
h = 19.79 m
