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alexgriva [62]
2 years ago
9

A 5 kilograms bowling ball is dropped out a window. It hits the ground, and bounces upward. The velocity change of the ball is n

oted to be 15 m/s downward and 12 m/s upward. What is the contact time for the ball if the force applied on the ball from the ground is equal to 10 N?
Physics
1 answer:
ioda2 years ago
4 0

Answer:

13.5

Explanation:

Mass: 5kg

Initial Velocity: -15

Final Velocity: 12

Force: 10

We can use the equation: Vf = Vi + at

We need to find acceleration, and we can use the equation, F=ma,

We have mass and the force so it would look like this, 10=5a, and 5 times 2 would equal 10, so acceleration would be 2.

Now we have all the variables to find time.

Back to Vf = Vi + at, plug the numbers in, 12 = -15 + 2(t)

Plugging them in into desmos gives 13.5 for time.

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umka21 [38]

The angular frequency of the wave is determined as 75.4 rad/s.

<h3>What is wave function?</h3>

A wave function is a mathematical equation for the motion of the wave.

y(x, t) = A sin(kx + ωt + Φ)

where;

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<h3>What is angular frequency?</h3>

The angular frequency is the angular displacement of any wave element per unit of time or the rate of change of the waveform phase.

<h3>Angular frequency</h3>

ω = 2πf

ω = 2π(12)

ω = 75.4 rad/s

Thus, the angular frequency of the wave is determined as 75.4 rad/s.

Learn more about angular frequency here: brainly.com/question/3654452

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1 year ago
A small object carrying a charge of -4.00 nC is acted upon by a downward force of 19.0 nN when placed at a certain point in an e
Gala2k [10]

Explanation:

Given that,

Charge acting on the object, q=-4\ nC=-4\times 10^{-9}\ C

Force acting on the object, F=19\ nC=19\times 10^{-9}\ C (in downward direction)

(a) The electric force acting in the electric field is given by :

F=qE

E is the electric field

E=\dfrac{F}{q}

E=\dfrac{19\times 10^{-9}\ N}{4\times 10^{-9}\ C}

E = 4.75 N/C

The direction of electric field is as same as electric force. But it is negative charge. So, the direction of electric field is in upward direction.

(b) The charge on the proton is, q=1.6\times 10^{-19}\ C

The force acting on the proton is :

F=qE

F=1.6\times 10^{-19}\times 4.75

F=7.6\times 10^{-19}\ N

If the charge on the proton is positive, the force on the proton is in upward direction.

Hence, this is the required solution.

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What principle of light’s behavior can be used to make a far away object appear closer and also make a small object appear large
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Answer: 7291.2 joules

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Work is done when force is applied on an object over a distance.

Thus, Workdone = Force X distance

Since Distance moved by box = 12 metres

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Recall that Force = Mass x acceleration due to gravity

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