A 5 kilograms bowling ball is dropped out a window. It hits the ground, and bounces upward. The velocity change of the ball is n
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Answer:
The value of bending stress on the pinion 35.38 M pa
Explanation:
Given data
m = 2 mm
Pressure angle = 20°
No. of teeth T = 17
Face width (b) = 20 mm
Speed N = 1650 rpm
Power = 1200 W
Diameter of the pinion gear
D = m T
D = 2 × 17
D = 34 mm
Velocity of the pinion gear
Form factor for the pinion gear is
Y = 0.303
Now
Force on gear tooth
F = 408.73 N
Now the bending stress is given by the formula
= 35.38 M pa
This is the value of bending stress on the pinion
To develop this problem it is necessary to apply the equations concerning Bernoulli's law of conservation of flow.
From Bernoulli it is possible to express the change in pressure as
Where,
Velocity
Density
g = Gravitational acceleration
h = Height
From the given values the change of flow is given as
Therefore between the two states we have to
The flow rate will have changed to 54.77 % of its original value.