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jeyben [28]
3 years ago
5

The point A on the above graph is an example of

Physics
2 answers:
Softa [21]3 years ago
5 0

Answer:

Interpolation

Explanation:

The graph shows that it falls between 2 values and interpolation means that you estimate the unknown values that fall between the 2 values. Hope this helps!

Eddi Din [679]3 years ago
4 0
Average method hope this helps
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How do I find net force when something has arrows all four directions with different N values for each?
Nimfa-mama [501]

In the vertical direction, take up to be positive and down to be negative. Then the net <u>vertical</u> force would be

5120 N - 4050 N = 1070 N

(it's positive, so the net vertical force is pointing upward)

In the horizontal direction, take right to be positive and left to be negative. Then the net <u>horizontal</u> force would be

950 N - 1520 N = -570 N

(negative means the net horizontal force points to the left)

So the net force on the balloon is the vector

<em>F</em> = (1070 N) <em>i</em> + (-570 N) <em>j</em>

(where <em>i</em> and <em>j</em> are the unit vectors in the horizontal and vertical directions, respectively)

The magnitude of the net force on the balloon is the magnitude of this vector:

<em>F</em> = √((1070 N)² + (-570 N)²)

<em>F</em> ≈ 1212 N

8 0
3 years ago
A car starts from rest with an acceleration of 2.84 m/s2 at the instant when a second car moving with a velocity of 25.7 m/s pas
vredina [299]

Answer:

464.69 m

Explanation:

First car

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}2.84t^2\\\Rightarrow s=1.42t^2

Second car

Distance = Speed × Time

\text{Distance}=25.7t

Here, the time taken and the distance traveled will be the same

Equating the two equations

1.42t^2=25.7t\\\Rightarrow t=\frac{25.7}{1.42}\\\Rightarrow t=18.09\ s

So, the first would have to move 1.42t^2=1.42\times 18.09^2=464.69\ m in order to overtake the second car.

7 0
4 years ago
You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f
Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

u = 0m/s

Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.

s = ut+\frac{1}{2} at^2

Replacing,

1 = u(0.141)+ \frac{1}{2} (9.8)(0.141)^2

u =6.4013m/s

The height of the acorn above the meter stick can be calculated as,

v^2 = u^2 +2gh

h = \frac{v^2-u^2}{2g}

h = \frac{6.4013^2-0^2}{2(9.8)}

h = 2.0906m

Also the top of the meter stick is 1.87m above the ground hence the height of the acorn above the ground is

h = 2.0906+1.87

h = 3.9606m

4 0
4 years ago
Nina is working with electricity and shortens the wires through which the current is flowing. What is Nina most likely trying to
wariber [46]
The answer is D i took the test but got it wrong but i got to see the answers
6 0
3 years ago
Read 2 more answers
What is the slant of a line on a graph called
tatiyna

Ashleybotello0129,

What is the slant of a line on a graph called "the slope." Slopes are in math, and science. Slopes look like slanted lines start from one side and to another.

Hope this helps!

7 0
3 years ago
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