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VLD [36.1K]
3 years ago
7

Please help! Will mark brainliest.

Physics
1 answer:
iogann1982 [59]3 years ago
6 0

Answer:

1122.8

Explanation:

12.73 kg x 9.8 m/s^2 x 9m

=1122.786

Rounded=1122.8

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A car moving in a straight line starts at x = 0 at t = 0 . It passes the point x = 30.0 m with a speed of 10.0 m/s at t = 3.00 s
Bogdan [553]

Answer:

a) v=20.3m/s

b) a=2.35m/s^2

Explanation:

From the exercise we know:

x_{1}=30m; v_{1}=10m/s; t_{1}=3s

x_{2}=375m; v_{2}=50m/s; t_{2}=20s

The formula for average velocity is:

v=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}

a) v=\frac{375m-30m}{20s-3s}=20.3m/s

The formula for average acceleration is:

a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}

b) a=\frac{(50-10)m/s}{(20-3)s}=2.35m/s^2

4 0
3 years ago
Which one of the following temperatures is equal to 5°C?
ss7ja [257]

5°C  =  41°F  =  278 K .
8 0
3 years ago
Read 2 more answers
I need help! plz, It's about energy. its just middle school science
Anit [1.1K]

Answer:

it would be 12/A

Explanation:

if you dived 5 by 12 youll get 60 and you cant get 60 y anything else in there so therefor its 12 :)

8 0
3 years ago
A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the h
zloy xaker [14]

Answer:

Speed of lighter ball is 4 m/s.

Explanation:

Applying the principle of conservation of linear momentum,

momentum before collision = momentum after collision.

m_{1}u_{1} + m_{2} u_{2} = m_{1}v_{1} - m_{2}v_{2}

m_{1} = 3 kg, u_{1} = 8 m/s, m_{2} = 2 kg, u_{2} = 0 m/s ( since it is at rest), v_{1} = 2 m/s, v_{2} = ?

(3 x 8) + (2 x 0) = (8 x 2) - (2 x v_{2})

24 + 0 = 16 - 2v_{2}

2v_{2} = 16 - 24

2v_{2} = -8

v_{2} = \frac{-8}{2}

   = -4 m/s

This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.

7 0
3 years ago
What is weight vs mass
Ray Of Light [21]
Weight is the measurement of the pull of gravity on an object, while mass is the measurement of the amount of matter that an object contains.
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