Answer:
about 42.35 m/s
Explanation:
Use the equation for accelerated motion (g), and with zero initial velocity that doesn't include time:
which for our case would reduce to:
then the velocity just before hitting would be about 42.35 m/s
Answer:
(a) 17.37 rad/s^2
(b) 12479
Explanation:
t = 95 s, r = 6 cm = 0.06 m, v = 99 m/s, w0 = 0
w = v / r = 99 / 0.06 = 1650 rad/s
(a) Use first equation of motion for rotational motion
w = w0 + α t
1650 = 0 + α x 95
α = 17.37 rad/s^2
(b) Let θ be the angular displacement
Use third equation of motion for rotational motion
w^2 = w0^2 + 2 α θ
1650^2 = 0 + 2 x 17.37 x θ
θ = 78367.87 rad
number of revolutions, n = θ / 2 π
n = 78367.87 / ( 2 x 3.14)
n = 12478.9 ≈ 12479
Answer:
Action force and Reaction force
Explanation:
The action force which is the balanced rock pushing down due to gravity and the reaction force pushing the equal amount of force. These two things are stated in Newtons third law, where he states that "Whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first." Also, he states that "all forces acts in pairs," meaning that every force exerted, there is an opposite force on the first.
The magnitude of the electric field inside the picture tube is 998.476 kN/C.
<h3>What is an electric field?</h3>
It is an area in the space where a charged particle experiences a force. It can be calculated by the formula,
Where,
= electric field produced
= charge = 
= distance = 
= Coulomb's constant = 
Put the values in the formula,
Therefore, the magnitude of the electric field inside the picture tube is 998.476 kN/C.
Learn more about the electric field:
brainly.com/question/3783640
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