3 years ago

What is the ideal mechanical advantage of a machine that changes only the direction of the input force?

1 answer:

6 0

Ideal M.A. is 1 I.e, load =effort

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Elis [28]

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slamgirl [31]

I think the answer is B

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disa [49]

Answer:

The question is incomplete. However, I believe, it is asking for the acceleration of the elevator. This is 3.16 m/s².

Explanation:

By Hooke's law, $F = ke$

F is the force on a spring, k is the spring constant and e is the extension or compression.

From the question,

$F = (1.08\text{ kN/m}) \times (6.0 \times 10^{-2}\text{ m}) = 64.8 \text{ N}$

This is the force on the mass suspended on the spring. Its acceleration, a, is given by

$F = ma$

$a = \dfrac{F}{m}$

$a = \dfrac{64.8 \text{ N}}{5\text{ kg}} = 12.96\text{ m/s}^2$

This acceleration is more than the acceleration due to gravity, g = 9.8 m/s². Hence the elevator must be moving up with an acceleration of

12.96 - 9.8 m/s² = 3.16 m/s²

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<span> (26 m/s)(1 rotation/0.62π m) ≈ 13.35 rotations/s that will do pig that'll do</span>

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