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julsineya [31]
3 years ago
14

The table below shows the precipitation in four locations:

Chemistry
2 answers:
Mars2501 [29]3 years ago
7 0
I believe its B


I hope this helps
xz_007 [3.2K]3 years ago
3 0

Answer:

Its b y'all hope this helps

Explanation:

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8moles of Na2Cr2O2 is how much mass​
Margaret [11]

\boxed{\boxed{\mathfrak{ 1\: mole \:of \:Na_2Cr_2O_2\: = \:it's \:Gram\: Mol. \: mass}} }

\underline{ \mathfrak{ Gram \:molecular \:mass \:of \: \red{ Na_2Cr_2O_2}}}

= 2 × 23 + 2 × 52 + 2 × 16

= 182 grams

1 mole of Na_2Cr_2O_2 weighs = 182 g

8 moles weigh = 8× 182

=\mathfrak{\blue {\boxed{\underline {1456 \: grams}}}}

or

\mathfrak{\blue {\boxed{\underline {1. 46 \:kg }}}}

5 0
3 years ago
A 225-g sample of aluminum was heated to 125.5 oc, then placed into 500.0 g water at 22.5 oc. (the specific heat of aluminum is
Sidana [21]
when  heat gained = heat lost 

when AL is lost heat and water gain heat

∴ (M*C*ΔT)AL = (M*C*ΔT) water

when M(Al) is the mass of Al= 225g 

C(Al) is the specific heat of Al = 0.9 

ΔT(Al) = (125.5 - Tf) 

and Mw is mass of water  = 500g

Cw is the specific heat of water = 4.81 

ΔT = (Tf - 22.5) 

so by substitution:

∴225* 0.9 * ( 125.5 - Tf) = 500 * 4.81 * (Tf-22.5)

∴Tf = 30.5 °C
7 0
3 years ago
Read 2 more answers
The mass of Jupiter is 300 times the mass of the earth. Jupiter orbits the sun with Jupiter = 11.9 yr in an orbit with Jupiter =
kondaur [170]

The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter's position will have the same orbital period regardless of mass. The correct answer is 11.9 yr. <u>Option C.</u>

As the Earth rotates on its axis creating day and night, it travels around the Sun in an elliptical orbit taking about 365 1/4 days to complete. The Earth's rotation axis is tilted with respect to the orbital plane. This creates seasons. The elliptical nature of the Earth's orbit is due to the first forces pushing the Earth away from the Sun's disk.

The momentum of this throw being greater the Earth's orbit would have been more elliptical or it might have been completely ejected from the solar system forever. The Earth's orbit defines a two-dimensional plane called the Ecliptic. It takes about 365 days for the earth to revolve around the sun. After years of analysis, Kepler found that Mars' orbit was likely elliptical, with the Sun at one of his focal points of the ellipse. This led Kepler to discover that all planets orbit the Sun in elliptical orbits and that the Sun is at one of his two focal points.

Learn more about The mass here:-brainly.com/question/26150306

#SPJ4

8 0
1 year ago
The chief advantage of the metric system over other systems of measurement is that it ____.
OlgaM077 [116]

The chief advantage of the metric system over other systems of measurement is that it B. is in multiples of 10.

This can be seen in the picture below that shows the prefixes of the metric system.


7 0
3 years ago
Read 2 more answers
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25 °C) form ideal solutions in all proportions. Let x1
jekas [21]

Answer:

y1 = 0.3162

y2 = 0.6838

Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

2-propanol P2° = 45.2 Torr

From Raoults law:

P(1-propanol) = P⁰ × X(1-propanol)

P(1-propanol) = 20.9 torr × 0.45 = 9.405

P(1-propanol) = 9.405 torr

Also P(2-propanol) = P⁰ × X(2-propanol)

P(2-propanol) = 45.2 torr × 0.45

P(2-propanol) = 20.34 torr

but the total pressure = sum of individual pressures

total pressure = 9.405 + 20.34

total pressure = 29.745 torr

given that y1 and y2 represent the mole fraction of each in the vapor phase

y1 = P1 / total pressure

y1 = 9.405/29.745

y1 = 0.3162

Since y1 + y2 = 1

y2 = 1 - y1

∴ y2 = 1 -  0.3162

y2 = 0.6838

cheers, i hope this helps.

7 0
3 years ago
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