First, we shall calculate the total number of moles present in the final solution.
Number of moles in 0.50 m NaCl = molarity * volume = 0.50 * 3.0 = 1.5 moles.
Number of moles in 0.2777m NaCl = molarity * volume = 0.2777 * 9.0 = 0.24993 moles
Total number of moles = 1.5 + 0.24993 = 1.74993 moles
Second, we shall calculate the total volume of the final solution.
Total volume = 3 + 9 = 12 litres.
The molarity = total number of moles / total volume = 1.74993 / 12 = 0.1458 m
Answer:
Molarity= 0.414M
Explanation:
Applying dilution formula
C1V1=C2V2
0.9×0.575= C2× 1.25
C2= 0.414M
Answer:
The answer to your question is V2 = 23.52 l
Explanation:
Data
Volume 1 = V1 = 22.5 l
Pressure 1 = P1 = 734 mmHg
Volume 2 = V2 = ?
Pressure 2 = 702 mmHg
Process
To solve this problem use Boyle's law.
P1V1 = P2V2
-Solve for V2
V2 = P1V1 / P2
-Substitution
V2 = (734 x 22.5) / 702
-Simplification
V2 = 16515 / 702
-Result
V2 = 23.52 l
-Conclusion
If we diminish the pressure, the volume will be higher.
Answer:
1.33 × 10²⁴ molecules CO₂
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Reading a Periodic Table
- Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
97.3 g CO₂
<u>Step 2: Define conversions</u>
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Convert</u>
= 1.33138 × 10²⁴ molecules CO₂
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules.</em>
1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂
