A block of iridium has a length of 4.20 cm, a width of 3.80 cm and a height

Chemistry

1 answer:

frutty [35]3 years ago

7 0

Answer:

d = 20.89 g/cm³

Explanation:

Given data:

Length of block = 4.20 cm

width of block = 3.80 cm

Height of block = 5.40 cm

Mass of block = 1800 g

Density of block = ?

Solution:

First of all we will calculate the volume.

V = l×w×h

V = 4.20 cm ×3.80 cm× 5.40 cm

v = 86.18 cm³

Density:

d =m/v

d =1800 g/ 86.18 cm³

d = 20.89 g/cm³

You might be interested in

What is the order in which electrons start filling the orbitals?

emmainna [20.7K]

a. 1s 2s 2p 3s 3p 4s 3d 4p is the correct option.

This gives the following order to fill the orbit: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, (8s, 5g, 6f, 7d, 8p, and 9s)

Aufbau's principle states that electrons fill low-energy atomic orbitals before they fill high-energy atomic orbitals. .. By following this rule, you can predict the electron configuration of an atom or ion.

There may be two electrons at the maximum of one orbit. Since the s subplane has only one orbit, it can hold up to two electrons. The p subplane has three orbitals, so it can hold up to six electrons. The d-subplane has five orbitals, so it can hold up to 10 electrons.

Learn more about electrons here:brainly.com/question/11316046

#SPJ4

4 0

1 year ago

Zn(s) + 2HCl(aq) -> ZnCl2(aq) + H2(g) Which half reaction correctly describes the oxidation that is taking place?

abruzzese [7]

Zn (s) -> Zn+2 (aq) + 2e-

Zn (s) with a neutral charge is oxidized and looses two electrons in the process to form ZnCl2 (aq) where Zn has a charge of 2+.

8 0

3 years ago

Read 2 more answers

Cual es la masa atomica del hidrogeno

Fittoniya [83]

El hidrógeno es el elemento químico de número atómico 1, representado por el símbolo H. Con una masa atómica de 1.00784 u es el más ligero de la tabla periódica de los elementos. Por lo general, se presenta en su forma molecular, formando el gas diatómico H₂ en condiciones normales.

4 0

2 years ago

What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm

Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

Difference in mass = 985.32 - 984.5 = 0.82 g

Explanation:

Part I :

$n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}$