Answer:
No, because pressure is determined by force and the area over which that force acts.
Explanation:
Answer:
0.1308
Explanation:
To keep the rider from sliding down, then the friction force
must at least be equal to gravity force 


where μ is the coefficient, N is the normal force acted by the rotating cylinder, m is the mass of a person and g = 9.81 m/s2 is the gravitational acceleration.
According to Newton's 3rd and 2nd laws, the normal force would be equal to the centripetal force
, which is the product of centripetal acceleration
and object mass m

Therefore


The centripetal acceleration is the ratio of velocity squared and the radius of rotation

Therefore

On the moon, the gravitational acceleration is 1/6 of 9.8 m/s², so
g = 9.8/6 = 1.633 m/s²
Launch speed = 35 m/s
Launch angle = 27° above the horizontal.
Therefore,
The horizontal velocity is
u = 35*cos(27) = 31.1852 m/s
The vertical launch velocity is
v = 35*sin(27) = 15.8897 m/s
Part A
When the ball reaches maximum height, the time requires is given by
0 = v - gt
t = v/g = 15.8897/1.6333 = 9.7286 s
This is one half of the time of flight, which is
2*9.7286 = 19.457 s
Answer: 19.46 s (2 sig. figs)
Answer:
Lift is the upward force on the wing acting perpendicular to the relative wind and perpendicular to the aircraft's lateral axis. Lift is required to counteract the aircraft's weight.
Explanation:
Answer:
d = 6.43 cm
Explanation:
Given:
- Speed resistance coefficient in silicon n = 3.50
- Memory takes processing time t_p = 0.50 ns
- Information is to be obtained within T = 2.0 ns
Find:
- What is the maximum distance the memory unit can be from the central processing unit?
Solution:
- The amount of time taken for information pulse to travel to memory unit:
t_m = T - t_p
t_m = 2.0 - 0.5 = 1.5 ns
- We will use a basic relationship for distance traveled with respect to speed of light and time:
d = V*t_m
- Where speed of light in silicon medium is given by:
V = c / n
- Hence, d = c*t_m / n
-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50
d = 0.129 m 12.9 cm
- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm