The centripetal force on the car as it goes around the second curve is twice that compared to the first.
What is Centripetal force?
It is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation.
The formula of Centripetal force is:
F(c) = (m* v^2) / r
Here,
At the first curve,
The curve of radius = r
The constant speed = v
At the second curve,
The car speed (v')= 2 v
The radius of the curve (r')=2 r
According to the formula of centripetal Force:
As the car goes around the second curve,
F'(c) = m*v'^2 / r'
F'(c) = m* (2*v)^2 / 2r
F'(c) = 2* F
Thus,
The centripetal force on the car as it goes around the second curve is twice that compared to the first.
Learn more about centripetal force here:
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T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r
where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance.
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect,
Point 1:
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r
Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m
The distance between the two points then is equal to 7.07 m.
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Since this is a distance/time graph, the speed at any time is the slope
of the part of the graph that's directly over that time on the x-axis.
At time t1 = 2.0 s
That's in the middle of the first segment of the graph,
that extends from zero to 3 seconds.
Its slope is 7/3 . v1 = 7/3 m/s .
At time t2 = 4.0 s
That's in the middle of the horizontal part of the graph
that runs from 3 to 6 seconds.
Its slope is zero.
v2 = zero .
At time t3 = 13 s.
That's in the middle of the part of the graph that's sloping down,
between 11 and 16 seconds.
Its slope is -3/5 . v3 = -0.6 m/s .
Answer:
B. moving faster than car B, but not necessarily accelerating
Explanation:
Velocity is the speed of something. So car A's velocity is greater than car B but does not mean car A is accelerating.