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scoundrel [369]
3 years ago
6

An advanced computer sends information to its various parts via infrared light pulses traveling through silicon fibers (n = 3.50

). To acquire data from memory, the central processing unit sends a light-pulse request to the memory unit. The memory unit processes the request, then sends a data pulse back to the central processing unit. The memory unit takes 0.50 ns to process a request. If the information has to be obtained from memory in 2.00 ns, what is the maximum distance the memory unit can be from the central processing unit?
Physics
1 answer:
sasho [114]3 years ago
8 0

Answer:

d = 6.43 cm

Explanation:

Given:

- Speed resistance coefficient in silicon n = 3.50

- Memory takes processing time t_p = 0.50 ns

- Information is to be obtained within T = 2.0 ns

Find:

- What is the maximum distance the memory unit can be from the central processing unit?

Solution:

- The amount of time taken for information pulse to travel to memory unit:

                            t_m = T - t_p

                            t_m = 2.0 - 0.5 = 1.5 ns

- We will use a basic relationship for distance traveled with respect to speed of light and time:

                           d = V*t_m

- Where speed of light in silicon medium is given by:

                           V = c / n

- Hence,              d = c*t_m / n

-Evaluate:           d = 3*10^8*1.5*10^-9 / 3.50

                           d = 0.129 m 12.9 cm

- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm

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Answer:

An atom always has the same number of electrons as protons. Electrons have an electric charge of -1 and protons have an electric charge of +1. Therefore, the charges of an atom's electrons and protons “cancel out.” This explains why atoms are neutral in electric charge.

Explanation:

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4 years ago
Two guitars are playing together producing a beat frequency. The first guitar is playing at a frequency of 867 Hz and the beat i
IgorLugansk [536]

Answer:

892 Hz or 842 Hz

Explanation:

Given

The frequency of first guitar is 867 Hz

Beat is produced for every 0·04 s

∴ Beat has a time period of 0·04 s

<h3>Beat frequency is defined as the inverse of the time period of the beat </h3>

Beat frequency = 1 ÷ (Time period) = 1 ÷ 0·04 = 25 Hz

Let the frequency of the second guitar be f Hz

<h3>Beat frequency is defined as the absolute difference between the two frequencies</h3>

∴ Beat frequency = (867 - f) or (f - 867)

First case

25 = 867 - f ⇒ f = 842 Hz

Second case

25 = f - 867 ⇒ f = 892 Hz

∴ Possible frequencies of second guitar could be 892 Hz or 842 Hz

4 0
3 years ago
A 2,000 kg rocket is launched 12 km straight up at a constant acceleration into the sky at which point the rocket is travelling
iogann1982 [59]

Answer:

797700000 J

Explanation:

From the question,

The work done by the rocket, is given as,

W = Ek+Ep............. Equation 1

Where Ek and Ep are the potential and the kinetic energy of the rocket respectively.

Ep = mgh............ Equation 2

Ek = 1/2mv²............. equation 3

Substitute equation 2 and equation 3 into equation 1

W = mgh+1/2mv².............. Equation 4

Where m = mass of the rocket, h = height, v = velocity of the rocket, g = acceleration due to gravity.

Given: m = 2000 kg, h = 12 km = 12000 m, v = 750 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 2000(12000)(9.8)+1/2(2000)(750²)

W = 235200000+562500000

W = 797700000 J

6 0
3 years ago
HELP ME !!!
NNADVOKAT [17]

Answer:

It would be cut in half.

Explanation:

If the momentum of the ball is cut into half, the velocity will also be halved.

The momentum of a body is the amount motion a body possess.

Momentum is given as;

       momentum= m x v

Given that;

 mass  = 1kg

 velocity  = 12m/s

Now find the momentum;

            momentum  = 1 x 12 = 12kgm/s

Halving the momentum = 6kgm/s

              mass = 1kg

 Momentum  = 1 x v

       6  = 1 x v

           v  = 6m/s

We see that the velocity reduces by half

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3 years ago
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