1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
scoundrel [369]
3 years ago
6

An advanced computer sends information to its various parts via infrared light pulses traveling through silicon fibers (n = 3.50

). To acquire data from memory, the central processing unit sends a light-pulse request to the memory unit. The memory unit processes the request, then sends a data pulse back to the central processing unit. The memory unit takes 0.50 ns to process a request. If the information has to be obtained from memory in 2.00 ns, what is the maximum distance the memory unit can be from the central processing unit?
Physics
1 answer:
sasho [114]3 years ago
8 0

Answer:

d = 6.43 cm

Explanation:

Given:

- Speed resistance coefficient in silicon n = 3.50

- Memory takes processing time t_p = 0.50 ns

- Information is to be obtained within T = 2.0 ns

Find:

- What is the maximum distance the memory unit can be from the central processing unit?

Solution:

- The amount of time taken for information pulse to travel to memory unit:

                            t_m = T - t_p

                            t_m = 2.0 - 0.5 = 1.5 ns

- We will use a basic relationship for distance traveled with respect to speed of light and time:

                           d = V*t_m

- Where speed of light in silicon medium is given by:

                           V = c / n

- Hence,              d = c*t_m / n

-Evaluate:           d = 3*10^8*1.5*10^-9 / 3.50

                           d = 0.129 m 12.9 cm

- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm

You might be interested in
A car goes around a curve of radius r at a constant speed v. Then it goes around a curve ofradius 2r at speed 2v. What is the ce
Rainbow [258]

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

What is Centripetal force?

It is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation.

The formula of Centripetal force is:

F(c) = (m* v^2) / r

Here,

At the first curve,

The curve of radius = r

The constant speed = v

At the second curve,

The car speed (v')= 2 v

The radius of the curve (r')=2 r

According to the formula of centripetal Force:

As the car goes around the second curve,

F'(c) = m*v'^2 / r'

F'(c) = m* (2*v)^2 / 2r

F'(c) = 2* F

Thus,

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

Learn more about centripetal force here:

<u>brainly.com/question/14317060</u>

#SPJ4

8 0
2 years ago
Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?
MrMuchimi
 T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r 

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance. 
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect, 

Point 1: 
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r

Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m 
The distance between the two points then is equal to 7.07 m.


</span>
8 0
3 years ago
Find the object's speeds v1, v2, and v3 at times t1=2.0s, t2=4.0s, and t3=13s.
Burka [1]
Since this is a distance/time graph, the speed at any time is the slope
of the part of the graph that's directly over that time on the x-axis.

At time  t1 = 2.0 s
That's in the middle of the first segment of the graph,
that extends from zero to 3 seconds.
Its slope is  7/3 .              v1 = 7/3 m/s .

At time  t2 = 4.0 s
That's in the middle of the horizontal part of the graph
that runs from 3 to 6 seconds.
Its slope is zero.
                                     v2 = zero .

At time  t3 = 13 s.
That's in the middle of the part of the graph that's sloping down,
between 11 and 16 seconds.
Its slope is  -3/5 .            v3 = -0.6 m/s .              
7 0
3 years ago
Read 2 more answers
Which of the following diagrams shows the path of deep water currents in the ocean?
Whitepunk [10]
I hope this helps. ^-^

6 0
4 years ago
If car A passes car B, then car A must be
Tcecarenko [31]

Answer:

B. moving faster than car B, but not necessarily accelerating

Explanation:

Velocity is the speed of something. So car A's velocity is greater than car B but does not mean car A is accelerating.

4 0
3 years ago
Other questions:
  • Electron groups consist of which of the following? A.Bonded pairs of electrons B.Lone-pair electrons C.Any atom that's an ion D.
    6·1 answer
  • The law of reflection states that if the angle of incidence is 81 degrees, the angle of reflection is ___ degrees.
    11·1 answer
  • Determine weather or not the equation below is balanced.
    5·1 answer
  • A solenoid has 332 turns and a length of 14 cm. If a current of 0.88 A produces a magnetic flux density of 0.28 T in the core of
    5·1 answer
  • A given 60uc piont charge located at origion
    13·2 answers
  • Which term best describes how fast and in what direction an object is moving at a particular moment? Question 2 options: acceler
    15·1 answer
  • The diagram below represents a flashlight that has been turned on. Which form of energy is being converted to electrical energy
    12·1 answer
  • A woman is walking at 4 m/s. She is accelerating at a rate of 1 m/s2. To find out what her velocity is after 3 seconds, what els
    8·2 answers
  • 8. How much energy was expended by a rocked that is launched at 90 degrees
    10·1 answer
  • Jus de fruits frais
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!