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Debora [2.8K]
3 years ago
12

In contact forces, _____.

Physics
2 answers:
lbvjy [14]3 years ago
8 0
Answer: B

Explanation:
MrRa [10]3 years ago
8 0

Answer:

B is the best answer for this

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The collision of the molecules of fluid inside the surface of the container best describes which of the following?
ki77a [65]
I think the correct answer from the choices listed above is option D. <span>The collision of the molecules of fluid inside the surface of the container best describes pressure inside the container. Hope this answers the question. Have a nice day.</span>
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3 years ago
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The mass after a physical change, such as ice melting into water, stays the same a. -true b. -false.
kupik [55]

Answer:

Yes, it can be destroyed.The total amount of matter (atoms) before and after a chemical reaction (change), remains the same.

Explanation:

hope this helps

3 0
3 years ago
Ch 26 HW
Ksivusya [100]

Answer:

Please see the attached picture for the answer.

Explanation:

5 0
3 years ago
Two samples of an ideal gas are initially at the same temperature and pressure. They are each compressed reversibly from a volum
Arisa [49]

Answer:In adiabatic case

Explanation:

Let us suppose Initial condition

P_1,V

be the initial pressure and volume of gas

and P_2,\frac{V}{2}

be the final pressure

\left ( a\right )In Isothermal case

Temprature is costant therefore

PV=constant

P_1V=P_2\frac{V}{2}

P_2=2P_1

for adiabatic case

PV^{\gamma }=constant

P_1V^{\gamma }=P_2\left (\frac{V}{2}\right )^{\gamma }

P_2=2^{\gamma }P_1

and we know\gamma is greater than 1

therefore In adiabatic case pressure will be high.

7 0
4 years ago
A mass of gas occupies 20 cm3 at 5 degrees Celcius and 760 mm Hg pressure. What is its volume at 30 degrees Celcius and 800 mm H
suter [353]

Answer:

20.7 cm³

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 20 cm³

Initial temperature (T1) = 5 °C

Initial pressure (P1) = 760 mm Hg

Final temperature (T2) = 30 °C

Final pressure (P2) = 800 mm Hg

Final volume (V2) =?

Next we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

Temperature (K) = Temperature (°C) + 273

Initial temperature (T1) = 5 °C

Initial temperature (T1) = 5 °C + 273 = 278 K.

Final temperature (T2) = 30 °C

Final temperature (T2) = 30 °C + 273 = 303 K.

Finally, we shall determine the new volume of the gas as follow:

Initial volume (V1) = 20 cm³

Initial temperature (T1) = 278 K

Initial pressure (P1) = 760 mm Hg

Final temperature (T2) = 303 K

Final pressure (P2) = 800 mm Hg

Final volume (V2) =?

P1V1/T1 = P2V2/T2

760 × 20 /278 = 800 × V2/303

Cross multiply

278 × 800 × V2 = 760 × 20 × 303

Divide both side by 278 × 800

V2 = (760 × 20 × 303) / (278 × 800)

V2 = 20.7 cm³

Therefore, the new volume of the gas is 20.7 cm³

3 0
4 years ago
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