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3 years ago

Does anyone know the ones that are blank

Chemistry

2 answers:

Mashutka [201]3 years ago

6 0

What is it asking for?

Ratling [72]3 years ago

3 0

Answer:

yeah whats it asking for

Explanation:

You might be interested in

What element can scratch a diomand?

borishaifa [10]

Answer:

another diamond ....theres nothing else that can that I know of.

3 0

3 years ago

Part B Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, Be.

dmitriy555 [2]

Answer: The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

Explanation:

There are 4 quantum numbers:

Principal Quantum number (n) specifies the energy of the electron in a shell.
Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of $+\frac{1}{2}$ or $-\frac{1}{2}$

Berylium (Be) is the 4th element of periodic table having electronic configuration of $1s^22s^2$

For electrons in 1s-orbital, the quantum numbers can be:

For first electron:

$n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=1\\l=0\\m=0\\s=-\frac{1}{2}$

For electrons in 2s-orbital, the quantum numbers can be:

For first electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}$

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

4 0

3 years ago

4. Define oxidation and reduction in terms of the gain or loss of electrons.

Andreyy89

$\mathbb\color{cyan}{\tiny A\scriptsize N\small S\large W\Large E\huge R}$

Oxidation is loss of electrons, gain of oxygen or loss of hydrogen.
Reduction is gain of electrons, loss of oxygen or gain or hydrogen.

3 0

2 years ago

A gas mixture contains 3.00 atm of H2 and 1.00 atm of O2 in a 1.00 L vessel at 400K. If the mixture burns to form water while th

sleet_krkn [62]

Answer:

$p_{H_2O}=2.00atm$

Explanation:

Hello!

In this case, according to the following chemical reaction:

$2H_2+O_2\rightarrow 2H_2O$

It means that we need to compute the moles of hydrogen and oxygen that are reacting, via the ideal gas equation as we know the volume, pressure and temperature:

$n_{H_2}=\frac{3.00atm*1.00L}{0.08206\frac{atm*L}{mol*K}*400K}=0.0914molH_2 \\\\n_{O_2}=\frac{1.00atm*1.00L}{0.08206\frac{atm*L}{mol*K}*400K}=0.0305molH_2$

Thus, the yielded moles of water are computed by firstly identifying the limiting reactant:

$n_{H_2O}^{by\ H_2} = 0.0914molH_2*\frac{2molH_2O}{2molH_2} =0.0914molH_2O\\\\n_{H_2O}^{by\ O_2} = 0.0305molO_2*\frac{2molH_2O}{1molO_2} =0.0609molH_2O$

Thus, the fewest moles of water are 0.0609 mol so the limiting reactant is oxygen; in such a way, by using the ideal gas equation once again, we compute the pressure of water:

$p_{H_2O}=\frac{0.0609molH_2O*0.08206\frac{atm*L}{mol*K}*400K}{1.00L}\\\\ p_{H_2O}=2.00atm$

Best regards!

7 0

3 years ago

What mass of carbon dioxide is produced upon the complete combustion of 26.5 L of propane (the approximate contents of one 5-gal

svet-max [94.6K]

Answer:

mCO2= 49.6932 kgCO2

Explanation:

Hello! Let's solve this!

First we propose the balanced equation C3H8 + 5O2 ---> 3CO2 + 4H2O

We see that each mole of C3H8 (propane) we get 3 moles of CO2

From the propane volume we can obtain the grams of propane used.

molpropane = 26.5L * (1000mL / 1L) * (0.621g / 1mL) * (1mol / 44g) = 374.01mol propane

mCO2 = 374.01molC3H8 * (3molCO2 / 1molC3H8) * (44gCO2 / 1molCO2) = 49369.32g * (1kg / 1000g) = 49.6932 kgCO2

mCO2= 49.6932 kgCO2

6 0

3 years ago