Answer:
it is ether a or b i think more b tho
Explanation:
Hope i could help
1) first, we need to write down the reaction equation for this combustion.
2C₈H₁₈ + 25O₂ ----> 16CO₂ + 18H₂O
2) we have the volume of gasoline, we can use the density to convert to grams
3.8 L = 3800 mL
3800 mL (0.79 g/ 1 mL)= 3002 grams
3) let's convert the grams to moles using the molar mass of gasoline
molar mass C₈H₁₈= (8 x 12.0) + (18 x 1.01)= 114.18 g/mol
3002 g (1 mol/ 114.18 grams) = 26.3 moles
4) let's use the balanced equation to convert moles of C₈H₁₈ to moles of water.
26.3 moles C₈H₁₈ (18 mol H₂O/ 2 moles C₈H₁₈)= 237 moles H₂O
5) finally, let's convert the moles to grams using the molar mass of water and then to Kg
molar mass of H₂O (2 x 1.01) + 16.0= 18.02 g/mol
237 mol H₂O (18.02 g/ 1 mol)= 4260 grams
4260 grams= 4.26 Kilograms
Answer:
12 number of moles of carbon dioxide are used.
Explanation:
Given data:
Number of moles of oxygen produced = 12 mol
Number of moles of CO₂ used = ?
Solution:
Chemical equation:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
Now we will compare the moles of oxygen with carbon dioxide.
O₂ : CO₂
6 : 6
12 : 12
Thus, 12 number of moles of carbon dioxide are used.
Answer:
They are highly lustrous metals which are resistant to corrosion. They are highly malleable and ductile so can be transformed into any shape or design.
Explanation:
Answer: faster than , less energy
