The movements of the tectonic plates
Answer:
balloon pushes you back
Explanation:
3rd Law: Every action has an equal and opposite reaction
So, when you let go of the balloon it's pushed forward so the balloon pushes you back
Answer:
a. It always points perpendicular to the contact surface.
Explanation:
"Normal" means perpendicular. Normal forces are always perpendicular to the contact surface.
Explanation:
Show that the motion of a mass attached to the end of a spring is SHM
Consider a mass "m" attached to the end of an elastic spring. The other end of the spring is fixed
at the a firm support as shown in figure "a". The whole system is placed on a smooth horizontal surface.
If we displace the mass 'm' from its mean position 'O' to point "a" by applying an external force, it is displaced by '+x' to its right, there will be elastic restring force on the mass equal to F in the left side which is applied by the spring.
According to "Hook's Law
F = - Kx ---- (1)
Negative sign indicates that the elastic restoring force is opposite to the displacement.
Where K= Spring Constant
If we release mass 'm' at point 'a', it moves forward to ' O'. At point ' O' it will not stop but moves forward towards point "b" due to inertia and covers the same displacement -x. At point 'b' once again elastic restoring force 'F' acts upon it but now in the right side. In this way it continues its motion
from a to b and then b to a.
According to Newton's 2nd law of motion, force 'F' produces acceleration 'a' in the body which is given by
F = ma ---- (2)
Comparing equation (1) & (2)
ma = -kx
Here k/m is constant term, therefore ,
a = - (Constant)x
or
a a -x
This relation indicates that the acceleration of body attached to the end elastic spring is directly proportional to its displacement. Therefore its motion is Simple Harmonic Motion.
Answer:
2.00 m/s²
Explanation:
Given
The Mass of the metal safe, M = 108kg
Pushing force applied by the burglar, F = 534 N
Co-efficient of kinetic friction, = 0.3
Now,
The force against the kinetic friction is given as:
Where,
N = Normal reaction
g= acceleration due to the gravity
Substituting the values in the above equation, we get
or
Now, the net force on to the metal safe is
Substituting the values in the equation we get
or
also,
acceleration of the safe
Therefore, the acceleration of the metal safe will be
acceleration of the safe=
or
acceleration of the safe=
or
acceleration of the safe=
Hence, the acceleration of the metal safe will be 2.00 m/s²