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uranmaximum [27]
3 years ago
8

The moon has much less gravitational force than earth. What would happen if you went to the moon?

Physics
1 answer:
Marta_Voda [28]3 years ago
7 0

Besides suffocating and inflating like a balloon in the Moon's lack of Oxygen, getting cooked during the Moon's daytime, getting frozen solid during the Moon's night-time, and having no access to the internet or any radio or TV stations, you would weigh only about 16% of what you weigh on Earth because of the Moon's lesser gravity.  

So like if you weigh 135 pounds on Earth AND you remembered to bring the bathroom scale with you when you left for the Moon, the scale would show that you weigh only a little over 22 pounds there.

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John goes grocery shopping with his mother. His job is to push the cart. The cart is
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Answer:

Beacause he has more grocceries and food heavy

Explanation:

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A boat takes off from a dock at 2.5 m/s and speeds up at 4.2 m/s squared for six seconds how far has the most traveled
GaryK [48]

The boat's position x relative to its starting point x_0=0 is determined by

x=x_0+v_0t+\dfrac12at^2

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x=\left(2.5\,\dfrac{\mathrm m}{\mathrm s}\right)(6\,\mathrm s)+\dfrac12\left(4.2\,\dfrac{\mathrm m}{\mathrm s^2}\right)(6\,\mathrm s)^2

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3 years ago
How much work is accomplished when a force of 250 N pushes a box across the floor for a distance of 50 meters?
IrinaK [193]
Work = force * distance
and newton*meters = Joule

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4 years ago
Which car has the most kinetic energy ??
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Read 2 more answers
A 1.0-m-diameter vat of liquid is 2.0 m deep. The pressure at the bottom of the vat is 1.3 atm. What is the mass of the liquid i
gladu [14]

Answer:

The mass of the liquid = 10538 kg

Explanation:

The pressure in a liquid is

P = ρgh ......................... Equation 1

ρ = P/gh ...................... Equation 2

Where P = pressure, ρ = density, g = acceleration due to gravity, h = height.

Given: p = 1.3 atm, h = 2.0 m, g = 9.81 m/s²

If,  1 atm = 1.013×10⁵ N/m²

Then, P = 1.3×1.013×10⁵ N/m² = 1.3169×10⁵ N/m²

Substituting in equation 2,

ρ  =  1.3169×10⁵/(9.81×2)

ρ =   1.3169×10⁵/19.62

 ρ = 6712.03 kg/m³.

But Density,

ρ  = m/v  

m =  ρ × v........................ Equation 3

Where m = mass of the liquid, v = volume of the liquid in the vat

v = πd²h/4, where d = diameter = 1.0 m, h = 2.0 m.

v = 3.14(1)²×2/4

v = 1.57 m³ also,  ρ =  6712.03 kg/m³.

Substituting into equation 3

m = 1.57×6712.03

m = 10537.887 kg

m ≈ 10538 kg.

Thus the mass of the liquid = 10538 kg

3 0
4 years ago
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