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uranmaximum [27]
3 years ago
8

The moon has much less gravitational force than earth. What would happen if you went to the moon?

Physics
1 answer:
Marta_Voda [28]3 years ago
7 0

Besides suffocating and inflating like a balloon in the Moon's lack of Oxygen, getting cooked during the Moon's daytime, getting frozen solid during the Moon's night-time, and having no access to the internet or any radio or TV stations, you would weigh only about 16% of what you weigh on Earth because of the Moon's lesser gravity.  

So like if you weigh 135 pounds on Earth AND you remembered to bring the bathroom scale with you when you left for the Moon, the scale would show that you weigh only a little over 22 pounds there.

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force is a derived quantity

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Do heavier objects fall more slowly than lighter objects?
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Which part of the electromagnetic spectrum is divided into seven ranges of wavelengths and is the part visible to the human eye
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a rocket, initially at rest, is fired vertically with a net upward acceleration of 12 m/s2 . at an altitude of 0.50 km, the engi
kobusy [5.1K]

The rocket travelled a maximum height at 1.0102 km.

Given,

The acceleration of a rocket (a) = 12 m/s²

The altitude of the rocket (s) =  0.50 km = 0.5×10³m

The maximum height of the rocket (h) = ?

Solution,

A rocket is a spacecraft, aircraft, vehicle or projectile that obtains thrust from a rocket engine.

The rate of change of the velocity of an object with respect to time is known as acceleration. It is denoted by (a).i.e. unit is m/s²

(a) = Δv/Δt

Where , Δv is change in velocity and Δt is change in time.

The rate of change in position with respect to time is known as velocity. i.e. Its unit is m/s.

(v)= Δx/Δt

Where,Δx is the change in position and Δt is change in time & v is velocity.

Therefore we know the equation of motion is written as,

v² = u² +2as

Where, v  is final velocity , u is initial velocity , a is acceleration and s is altitude of the rocket.

Then putting the value ,

v² = 0 + ( 2× 10 × 0.5×10³)m/s

v² = \sqrt{10000} m/s

v = 100 m/s

Therefore, at altitude of 0.50 km the initial velocity of rocket (u) will be 100 m/s, final velocity v become zero and under free falling the acceleration will be taken (-g) then equation of motion can be given as ,

v² = u² - 2(g)h

h = (v²- u² ) / 2g

h = 10,000/2×9.8

h = 510.2 m

So that the rocket travelled the maximum height ,

(h)= (0.5 km + 510.2m)

(h) = 1.0102 km

Hence, the rocket travelled at the maximum height h is 1.0102 km

To know more about acceleration

brainly.com/question/15135960

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2 years ago
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