Which instrument is used to measure the height of a 20 litre jerrican

I need help with these questions

stira [4]

Answer:

was there a reading that your class did on this

Explanation:

5 0

4 years ago

11

GarryVolchara [31]

Explanation:

Given that,

The pilot directs the aircraft to fly due north at 600km/h.

A side-wind blows at 100km/h towards the east.

We need to find the aircraft's resultant velocity. et it be v. It can be calculated as follows :

$v=\sqrt{600^2+100^2} \\\\v=608.27\ m/s$

For direction,

$\tan\theta=\dfrac{600}{100}\\\\\tan\theta=6\\\\\theta=\tan^{-1}(6)\\\\\theta=80.53^{\circ}$

So, the aircraft's resultant velocity is 608.27 km/h and it is at and angle of 80.53°.

7 0

3 years ago

What has to be true about mass if a small object (like a metal ball) has a high density? A: The mass has to be high compared to

inysia [295]

<span>Since density is equal to mass divided by volume, we can determine the relationship between mass, density, and volume. Therefore, we can automatically know that the answer must either be A or B, since this information is determinable. The prompt lists the object as small. Therefore, we know that density is high, but volume is low. Let's examine the equation (D = M/V), where d = density, m = mass, and v = volume. In order for any number to be divided by a smaller number and have the end result be a higher number, the numerator (i.e. mass) must be bigger than the denominator (i.e. volume). We can also see that this is true by substituting in somewhat random numbers for d, m, and v. D = M / V 5 = 10 / 2 10 > 2 M > V In conclusion, your answer is D.</span>

6 0

3 years ago

Read 2 more answers

How would you find the speed of a ball thrown in to the air- it takes 6 seconds to get tho the top. The height is not given.

Alecsey [184]

You would need to know how fast you threw the ball in the air once that then multiply the seeped and the time to get your answer<span />

7 0

3 years ago

Four +2 µC point charges are at the corners of a square of side 2 m. Find the potential at the center of the square (relative to

Romashka [77]

Answer:

(a) 51428.59 J/C

(b) 25714.29 J/C

(c) 0 J/C

Explanation:

Parameters given:

Q1 = 2 * 10^-6 C

Q2 = 2 * 10^-6 C

Q3 = 2 * 10^-6 C

Q4 = 2 * 10^-6 C

=> Q1 = Q2 = Q3 = Q4 = Q

Side of the square = 2m

The center of the square is the midpoint of the diagonals, i.e. Using Pythagoras theorem:

BD² = 2² + 2²

BD² = 8

BD = √(8) = 2.8m

OD = 1.4m

(The attached diagram explains better)

Hence, the distance between the center and each point charge, r, is 1.4m.

Electric Potential, V = kQ/r

k = Coulombs constant

(a) If all charges are positive:

V(Total) = V1 + V2 + V3 + V4

V1 = Potential due to Q1

V2 = Potential due to Q2

V3 = Potential due to Q3

V4 =Potential due to Q4

Since Q1 = Q2 = Q3 = Q4 = Q

=> V1 = V2 = V3 = V4

=> V(Total) = 4V1

V = (4 * 9 * 10^9 * 2 * 10^-6)/1.4

V = 51428.59J/C

(b) If 3 charges are positive and 1 is negative:

Since Q1 = Q2 = Q3 = Q

and Q4 = -Q

The total potential becomes:

V(Total) = V1 + V2 + V3 - V4

Since V1, V2, V3 and V4 have the same value,

V(Total) = V1 + V2

V(Total) = 2V1

V(Total) = (2 * 9 * 10^9 * 2 * 10^-6)/1.4

V(Total) = 25174.29 J/C

(c) Two charges are positive and two are negative:

Since Q1 = Q2 = Q

and Q3 = Q4 = -Q

The total potential becomes:

V(Total) = V1 + V2 - V3 - V4

Since V1, V2, V3 and V4 have the same value,

V(Total) = 0 J/C

8 0

3 years ago

Which instrument is used to measure the height of a 20 litre jerrican​

Which instrument is used to measure the height of a 20 litre jerrican