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marusya05 [52]
3 years ago
12

What is the displacement for a driver who travels 10 km to get to a point that is 4 km from his starting point

Physics
1 answer:
Gnoma [55]3 years ago
5 0

His displacement is 4 km. The length of the route that he takes to get there is not relevant in measuring his displacement.

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Under water turbans that are placed at the above to middle of the ocean they are used to capture kinetic motion
7 0
3 years ago
On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the
Nina [5.8K]

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

\frac{F_E}{F_G}=\frac{qE}{mg}              (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764

Then, the gravitational force is 0.764 times the electric force on the particle

b)

The acceleration of the particle is obtained by using the second Newton law:

F_E-F_G=ma\\\\a=\frac{qE-mg}{m}

you replace the values of all variables:

a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

7 0
3 years ago
What is the equation: If F=10 N, a=5 m/s², m=?
Romashka-Z-Leto [24]

Answer:

2 kg

Explanation:

Remember:

F = m * a       re-arrange to

F/a   = m      substitute in the given values

10 / 5   =   2 kg

8 0
2 years ago
Please I need the answer right now will mark you brainliest ​
Dmitrij [34]

Answer:

Explanation:

what do u need help with

3 0
2 years ago
Read 2 more answers
Who much force is needed to accelerate a 68 kilogram-skier at a Rate of 1.2 m/sec
liberstina [14]
If F =m*a
and the question says how much force the s needed to accelerate a 68kg skier to a rate of 1.2ms^-2
Then F = 68*1.2
7 0
3 years ago
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