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marusya05 [52]
3 years ago
12

What is the displacement for a driver who travels 10 km to get to a point that is 4 km from his starting point

Physics
1 answer:
Gnoma [55]3 years ago
5 0

His displacement is 4 km. The length of the route that he takes to get there is not relevant in measuring his displacement.

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zloy xaker [14]

Answer:

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Explanation:

6 0
2 years ago
During which two time intervals does the particle undergo equal displacement?
san4es73 [151]

Answer:

BC and DE

Explanation:

In the given figure, the velocity time graph is shown. We know that the area under v-t curve gives the displacement of the particle.

Area under AB, d_1=\dfrac{1}{2}\times 2\times 10=10\ m

Area under BC, d_2=\dfrac{1}{2}\times 2\times 4=4\ m

Area under CD, d_3=\dfrac{1}{2}\times 2\times 7=7\ m

Area under DE, d_4=\dfrac{1}{2}\times 2\times 4=4\ m

Area under EF, d_5=\dfrac{1}{2}\times 2\times 3=3\ m

So, form above calculations it is clear that, during BC and DE undergo equal displacement. Hence, the correct option is (c) "BC and DE = 4 meters".

4 0
3 years ago
What is 1.0 x 10^9 in standard form?
jasenka [17]
1.0 x 10^9= 1000000000
3 0
3 years ago
A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on
Nutka1998 [239]

Answer:

60N

Explanation:

in this case the minimum amount of force required must be equal to the friction Force. i.e <u>Newton</u><u>'s</u><u> </u><u>first</u><u> </u><u>law</u><u> of</u><u> </u><u>mot</u><u>ion</u><u>.</u>

therefore the maximum amount of frictional force is equal to the applied force which is 60N.

because of the net force acting on the object is zero the object is in constant motion . i.e equal and opposite force must be applied so that the object is in constant velocity therefore the total frictional force must be 60N

8 0
3 years ago
Which of these is not true about the proton?
bulgar [2K]

Answer:

Option C is the untrue statement.

5 0
3 years ago
Read 2 more answers
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