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Otrada [13]
3 years ago
13

Anyone? Pleasee help

Mathematics
1 answer:
xeze [42]3 years ago
8 0

Answer:

Angle 1 = 128

Angle 2 = 52

Angle 3 = 68

Angle 4 = 60

Angle 5 = 124

Step-by-step explanation:

Had to use supplementary theorem, vertical angles theorem, and that the angles of a triangle add up to 180.

I hope this helps!

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Gary lost 17 pounds while on a diet, but gained 8 pounds back. Which number is the additive inverse of the change in Gary's weig
satela [25.4K]
If Gary lost 17 pounds and gained 8 pound back, then we have
 -17 pounds + 8 pounds = -9 pounds.
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 That is, Gary lost 9 pounds of weight.
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2 years ago
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Solve the inequality.<br> 5x - 7 &lt; 8x + 8<br> The solution set is x |
timofeeve [1]

Answer:

- 5 < x

Step-by-step explanation:

To solve, we need to isolate the variable: x

5x - 7 < 8x + 8

Subtract 5x from both sides

5x -  5x -7 < 8x -5x + 8

- 7 < 3x + 8

Subtract 8 from both sides

- 7 -8 < 3x + 8 -8

-15< 3x

Divide both sides by 3

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- 5 < x

5 0
3 years ago
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Find the area of the shaded region. Round the the nearest tenth.
Brums [2.3K]

Answer:

226.084 sq.m.

Step-by-step explanation:

Radius of circle = 18.6 cm

Area of sector = \frac{\theta}{360^{\circ} }\pi r^2

Area of sector = \frac{123}{360} \times 3.14 \times (18.6)^2

Area of sector = 371.157 m^2

Area of triangle = \frac{1}{2} \times a \times b \times Sin x

a = OA = radius = 18.6 cm

b = OB = radius = 18.6 cm

x =123 °

Substitute the values in the formula

Area of triangle = \frac{1}{2} \times 18.6 \times 18.6 \times Sin 123

Area of triangle = 145.073 m^2

So, Area of shaded region = Area of sector - Area of triangle

                                            =371.157 m^2-145.073 m^2

                                            =226.084 m^2

Hence the area of the shaded region is 226.084 sq.m.

5 0
3 years ago
jill measured the length of her eraser. She wrote 5 on her paper without the unit. Which metric unit of measure should Jill incl
choli [55]
Its either centimeters or inches.
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7 0
3 years ago
Find the value of x
Paladinen [302]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • x = 12°

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:2x + 6 + 5x + 90 = 180

[ by linear pair ]

\qquad❖ \:  \sf \:7x + 6 = 180 - 90

\qquad❖ \:  \sf \:7x + 6 = 90

\qquad❖ \:  \sf \:7x = 90 - 6

\qquad❖ \:  \sf \:7x = 84

\qquad❖ \:  \sf \:x = 84 \div 7

\qquad❖ \:  \sf \:x = 12

\qquad \large \sf {Conclusion}  :

\qquad❖ \:  \sf \:x = 12 \degree

7 0
2 years ago
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