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vlada-n [284]
3 years ago
7

What are the first six non-zero multiples of the number 7

Mathematics
1 answer:
7nadin3 [17]3 years ago
6 0
7, 14, 21, 28, 35, 42
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Reduce fraction: a^3+a^2b/5a times 25/3b+3a
Margaret [11]

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\frac{5a}{3}

EXPLANATION

The given fractions are:

\frac{{a}^{3}  +  {a}^{2} b}{5a}  \times  \frac{25}{3b + 3a}

We factor to obtain:

\frac{{a}^{2}(a  +   b)}{5a}  \times  \frac{25}{3(a + b)}

We cancel the common factors to get:

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\frac{5a}{3}

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