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kondaur [170]
3 years ago
5

The SI unit of average spped and velocity.​

Physics
1 answer:
Verdich [7]3 years ago
3 0

<em>meter per</em><em> </em><em>second</em><em> </em><em>is </em><em>the </em><em>main </em><em>answer </em><em>of</em><em> </em><em>both</em>

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4. An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5
Nata [24]

Answer:

11.9 m/s

*<em>But</em><em> </em><em>if</em><em> </em><em>you</em><em> </em><em>need</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>with</em><em> </em><em>sig</em><em> </em><em>figs</em><em> </em><em>it</em><em> </em><em>should</em><em> </em><em>be</em><em> </em><em>10m</em><em>/</em><em>s</em><em> </em><em>(</em><em>1sf</em><em>)</em><em> </em><em>or</em><em> </em><em>12m</em><em>/</em><em>s</em><em> </em><em>(</em><em>2sf</em><em>)</em>

Explanation:

{vf}^{2}  -  {vi}^{2}  = 2ad

{vf}^{2}  = 2ad +  {vi}^{2}

{vf}^{2}  = 2 \times 1.5 \times 20 +  {9}^{2}

{vf}^{2}  = 60 + 81

{vf}^{2}  = 141

vf =  \sqrt{141}

vf = 11.874

best answer if it worked

3 0
3 years ago
Please help me!
vovikov84 [41]

It is A. Im taking the test right now.

8 0
3 years ago
Read 2 more answers
PLEASE ANYONE CAN HELP ME !E.x/A block of metal has a volume of 0.09 m3
LuckyWell [14K]

Answer:

B = 1058.4  N

Explanation:

Given that,

The volume of a metal block, V = 0.09 m³

The density of fluid, d = 1200 kg/m³

We need to find the buoyant force when it's Completely  immersed in brine. The formula for the buoyant force is given by :

B=\rho gV

g is acceleration due to gravity

B=1200\times 9.8\times 0.09\\\\B=1058.4\ N

So, the required buoyant force is 1058.4  N.

3 0
3 years ago
Friction, conduction and induction are three ways of creating a static charge on an object. Which method or methods will produce
Agata [3.3K]
Friction as it will move charge (electrons) from one object to another
5 0
3 years ago
A bullet is fired vertically upward a velocity of 80m/s to what height will the bullet rise above the point of projection​
frozen [14]

Answer:

The bullet will rise 320 meters above the point of projection.

Explanation:

Assuming that air friction is negligent we can use the kinematic equation:

v_{2} ^2=v_{1} ^2+2(-a)d\\0\frac{m^2}{s^2} =6400\frac{m^2}{s^2} +2(-10\frac{m}{s^2} )d\\-6400\frac{m^2}{s^2} =(-20\frac{m}{s^2}) d\\320m=d

*acceleration is negative (-a) as it is acting in the opposite direction of the motion of the bullet.*

3 0
3 years ago
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