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kondaur [170]
3 years ago
5

The SI unit of average spped and velocity.​

Physics
1 answer:
Verdich [7]3 years ago
3 0

<em>meter per</em><em> </em><em>second</em><em> </em><em>is </em><em>the </em><em>main </em><em>answer </em><em>of</em><em> </em><em>both</em>

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A 2.5 kg steel gasoline tank can holds 20.0 L of gasoline when full. What is the average density (in Kg/m^3) of the full gas can
yarga [219]

Answer:

D=792.3\ kg/m^3

Explanation:

<u>Average Density </u>

The density of an object of mass m and volume V is

\displaystyle D=\frac{m}{V}

If we know the density and the volume occupied by the object, the mass can be computed as

m=D.V

The tank can hold 20 L of gasoline when full. Converting to cubic meters

V_g=20*0.001=0.02\ m^3

That's the volume of the gasoline it contains. Knowing the density of the gasoline, we get the mass of gasoline.

m_g=680*0.02=13.6\ kg

To know the total mass of both, we add the 2.5 kg of the tank

m=m_t+m_g=13.6+2.5=16.1\ kg

The volume of the tank is computed solving for V

\displaystyle V=\frac{m}{D}

\displaystyle V_t=\frac{2.5}{7800}=3.205\times 10^{-4}\ m^3

The total volume is

V=V_g+V_t=0.02+3.205\times 10^{-4}=0.0203\ m^3

The average density is

\displaystyle D=\frac{16.1}{0.0203}

\boxed{D=792.3\ kg/m^3}

7 0
3 years ago
A second baseman tosses the ball to the first baseman, who catches it at the same level from which it was thrown. The throw is m
Anit [1.1K]
 <span>(a) 

Taking the angle of the pitch, 37.5°, and the particle's initial velocity, 18.0 ms^-1, we get: 

18.0*cos37.5 = v_x = 14.28 ms^-1, the projectile's horizontal component. 

(b) 
To much the same end do we derive the vertical component: 

18.0*sin37.5 = v_y = 10.96 ms^-1 

Which we then divide by acceleration, a_y, to derive the time till maximal displacement, 

10.96/9.8 = 1.12 s 

Finally, doubling this value should yield the particle's total time with r_y > 0 

<span>2.24 s

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span></span>
6 0
3 years ago
How tall would a tower need to be if the period of a pendulum were 30. seconds
Virty [35]
We use the following expression

T = 2*pi *sqrt(l/g)

Where T is the period of the pendulum

l is the length of the pendulum

and g the acceleration of gravity

We solve for l

l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m

The tower would need to be at least 223.413 m high
4 0
3 years ago
Two square air-filled parallel plates that are initially uncharged are separated by 1.2 mm, and each of them has an area of 190
julia-pushkina [17]

Answer:

5.5\cdot 10^{-11} C

Explanation:

The capacitance of the parallel-plate capacitor is given by:

C=\epsilon_0 \frac{A}{d}

where

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

A=190 mm^2 = 190 \cdot 10^{-6} m^2 is the area of the plates

d=1.2 mm = 0.0012 m is the separation between the plates

Substituting,

C=(8.85\cdot 10^{-12}) \frac{190 \cdot 10^{-6}}{0.0012}=1.4\cdot 10^{-12}F

The energy stored in the capacitor is given by

U=\frac{Q^2}{2C}

Since we know the energy

U=1.1 nJ = 1.1 \cdot 10^{-9} J

we can re-arrange the formula to find the charge, Q:

Q=\sqrt{2UC}=\sqrt{2(1.1\cdot 10^{-9} J)(1.4\cdot 10^{-12}F )}=5.5\cdot 10^{-11} C

8 0
3 years ago
Solve the following system of equations by using either substitution or elimination.
strojnjashka [21]
I believe that the answer to the question provided above are the following;

x = 29.8410

y = 16.6794

z = -1.2642
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
5 0
3 years ago
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