Answer:
in 1 second 3m, in 2 seconds 6m, in 3 seconds 9m.
Explanation:
distance=speed × time
Answer:
a) I = 0 N s, b) v = -3.935 m / s, c) vf = 3.935 m / s, d) y = 0.790 m
Explanation:
a) Let's start by defining the upward direction (+ y) as positive. For this part of the exercise we must use the momentum relationship
I = ∫F dt
The force of the woman on the floor is given and by action and rection the floor exerts on the woman a force of equal magnitude, but opposite direction
I = ∫ (9200 t - 11500 t2) dt
I = 9200 t² / 2 - 11500 t³ / 3
We evaluate between the lower limit t = 0 and upper limit t = 0.800 s
I = 9200 (0.8² -0) - 11500 (0.8³ -0)
I = 5888 -5888
I = 0 N s
Directed from the floor to the woman
b) For this part we use kinematics
v² = v₀² - 2g y
v = √ (0 - 2 9.8 (-0.79))
v = 3.935 m / s
The speed direction is down
c) for this we use the relationship between momentum and the amount of movement
I = ΔP
I = m vf - m v₀
vf = (I + m v₀) / m
This is the impulse of women on the floor
vf = ( 0 + 68 (3.935)) / 68
vf = 3.935 m / s
d) let's use kinematics
v₂ = v₀² - 2gy
0 = v₀² - 2gy
y = v₀² / 2g
y = 3.935²/2 9.8
y = 0.790 m
Answer:
1.38 x 10^-18 J
Explanation:
q = - 1.6 x 10^-19 C
d = 5 x 10^-10 m
the potential energy of the system gives the value of work done
The formula for the potential energy is given by
So, the total potential energy of teh system is
As all the charges are same and the distance between the two charges is same so the total potential energy becomes
K = 9 x 10^9 Nm^2/C^2
By substituting the values
U = 1.38 x 10^-18 J
Explanation:
Given parameters:
Distance = 15miles north = 24140.2m
Initial velocity = 0m/s
Final velocity = 4m/s
Unknown:
Speed, velocity and acceleration = ?
Solution:
The speed is the distance divide by time. It is a scalar quantity and has no directional attribute.
Speed = 
The speed of the student is 4m/s
Velocity is the displacement divided by time. It is a vector quantity which specifies the direction and magnitude;
Velocity = 
The velocity of the student is 4m/s due north
Acceleration is the change in velocity with time;
To find the acceleration, we use
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
4² = 0² + 2x a x 24140.2
a = 
= 0.00033m/s²
This electric force calculator will enable you to determine the repulsive or attractive force between two static charged particles. Continue reading to get a better understanding of Coulomb's law, the conditions of its validity, and the physical interpretation of the obtained result.
How to use Coulomb's law
Coulomb's law, otherwise known as Coulomb's inverse-square law, describes the electrostatic force acting between two charges. The force acts along the shortest line that joins the charges. It is repulsive if both charges have the same sign and attractive if they have opposite signs.
Coulomb's law is formulated as follows:
F = keq₁q₂/r²
where:
F is the electrostatic force between charges (in Newtons),
q₁ is the magnitude of the first charge (in Coulombs),
q₂ is the magnitude of the second charge (in Coulombs),
r is the shortest distance between the charges (in m),
ke is the Coulomb's constant. It is equal to 8.98755 × 10⁹ N·m²/C². This value is already embedded in the calculator - you don't have to remember it :)
Simply input any three values
