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3 years ago

A box is pushed horizontally with constant speed across a rough horizontal surface.

Physics

1 answer:

Natasha_Volkova [10]3 years ago

6 0

Answer:

what is the answers? so i can't answer.

Explanation:

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A broom with a long handle balances at its centre of gravity as shown in the figure. If you cut the broom into two parts through

pantera1 [17]

Answer:

c) Both the parts will weigh the same

Explanation:

center of gravity is based on weight so if you cut down the center of gravity you would have 2 equal parts

(might be D if it is cutting against the center of gravity)

6 0

3 years ago

Back in their laboratory, the team of scientists carefully measure the changes in density of a freshwater sample as they decreas

BabaBlast [244]

Answer: As the temperature of the water decreases from 20 degrees celsius to 4 degrees celsius, the density increases.

Explanation:

7 0

2 years ago

Read 2 more answers

If a ball is thrown straight up into the air with an initial velocity of 65 ft/s, its height in feet after t seconds is given by

fgiga [73]

Answer:

a) $v_{1}=\frac{(62.5-66)ft}{(2.5-2)s}=-7ft/s$

$v_{2}=\frac{(65.94-66)ft}{(2.1-2)s}=-0.6ft/s$

$v_{3}=\frac{(66.0084-66)ft}{(2.01-2)s}=0.84ft/s$

$v_{4}=\frac{(66.001-66)ft}{(2.001-2)s}=1ft/s$

b) $v=65-32(2)=1ft/s$

Explanation:

From the exercise we got the ball's equation of position:

$y=65t-16t^{2}$

a) To find the average velocity at the given time we need to use the following formula:

$v=\frac{y_{2}-y_{1} }{t_{2}-t_{1} }$

Being said that, we need to find the ball's position at t=2, t=2.5, t=2.1, t=2.01, t=2.001

$y_{t=2}=65(2)-16(2)^{2} =66ft$

$y_{t=2.5}=65(2.5)-16(2.5)^{2} =62.5ft$

$v_{1}=\frac{(62.5-66)ft}{(2.5-2)s}=-7ft/s$

$y_{t=2.1}=65(2.1)-16(2.1)^{2} =65.94ft$

$v_{2}=\frac{(65.94-66)ft}{(2.1-2)s}=-0.6ft/s$

$y_{t=2.01}=65(2.01)-16(2.01)^{2} =66.0084ft$

$v_{3}=\frac{(66.0084-66)ft}{(2.01-2)s}=0.84ft/s$

$y_{t=2.001}=65(2.001)-16(2.001)^{2} =66.001ft$

$v_{4}=\frac{(66.001-66)ft}{(2.001-2)s}=1ft/s$

b) To find the instantaneous velocity we need to derivate the equation

$v=\frac{df}{dt}=65-32t$

$v=65-32(2)=1ft/s$

7 0

3 years ago

What is the momentum of a car with a mass of 1,300 kg traveling at a speed of 28 m/s?

Vlad1618 [11]

Answer:

<h3>The answer is 36,400 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 1,300 kg

speed / velocity = 28 m/s

We have

momentum = 1,300 × 28

We have the final answer as

Hope this helps you

7 0

3 years ago

A circus tightrope walker weighing 800 N is standing in the middle of a 15 meter long cable stretched between two posts. The cab

Lorico [155]

Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

Fₓ-Fₓ = 0

Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis

$F_{y} + F_{y} - W =0$

2 $F_{y}$ = W

let's use trigonometry to find the angles

tan θ = y / x

θ = tan⁻¹ (0.30 / 0.50 L)

θ = tan⁻¹ (0.30 / 0.50 15)

θ = 2.29º

the components of stress are

F_{y} = T sin θ

we substitute

2 T sin θ = W

T = W / 2sin θ

T = $\frac{ 800}{ 2sin 2.29}$

T = 10010 N

4 0

3 years ago